CODEWITHSUNDEEP
scalacase-class
schlicht
schlicht

Reputation: 4775

Building variations of nested case classes

So I got something like this:

abstract class Term
case class App(f:Term,x:Term) extends Term
case class Var(s:String) extends Term
case class Amb(a:Term, b:Term) extends Term //ambiguity

And a Term may look like this: 

App(Var(f),Amb(Var(x),Amb(Var(y),Var(z))))

So what I need is all variations that are indicated by the Amb class. This is used to represent a ambiguous parse forest and I want to type check each possible variation and select the right one. In this example I would need:

App(Var(f),Var(x))
App(Var(f),Var(y))
App(Var(f),Var(z))

Whats the best way to create these variations in scala? Efficiency would be nice, but is not really requirement. If possible I like to refrain from using reflection.

Upvotes: 6

Views: 599

Answers (3)

schlicht
schlicht

Reputation: 4775

Since my abstract syntax is fairly large (and I have multiple) and I tried my luck with Kiama. So here is the version Travis Brown and Mark posted with Kiama.

Its not pretty, but I hope it works. Comments are welcome.

  def disambiguateRule: Strategy = rule {
    case Amb(a: Term, b: Term) =>
      rewrite(disambiguateRule)(a).asInstanceOf[List[_]] ++
      rewrite(disambiguateRule)(b).asInstanceOf[List[_]]
    case x => 
      val ch = getChildren(x)
      if(ch.isEmpty) {
        List(x)
      }
      else {
        val chdis = ch.map({ rewrite(disambiguateRule)(_) }) // get all disambiguate children
        //create all combinations of the disambiguated children
        val p = combinations(chdis.asInstanceOf[List[List[AnyRef]]]) 
        //use dup from Kiama to recreate the term with every combination
        val xs = for { newchildren <- p } yield dup(x.asInstanceOf[Product], newchildren.toArray)
        xs
      }
  }

  def combinations(ll: List[List[AnyRef]]): List[List[AnyRef]] = ll match {
    case Nil      => Nil
    case x :: Nil => x.map { List(_) }
    case x :: xs  => combinations(xs).flatMap({ ys => x.map({ xx => xx :: ys }) })
  }

  def getChildren(x: Any): List[Any] = {
    val l = new ListBuffer[Any]()
    all(queryf {
      case a => l += a
    })(x)
    l.toList
  }

Upvotes: 0

Travis Brown
Travis Brown

Reputation: 139048

You can do this pretty cleanly with a recursive function that traverses the tree and expands ambiguities:

sealed trait Term
case class App(f: Term, x: Term) extends Term
case class Var(s: String) extends Term
case class Amb(a: Term, b: Term) extends Term

def det(term: Term): Stream[Term] = term match {
  case v: Var    => Stream(v)
  case App(f, x) => det(f).flatMap(detf => det(x).map(App(detf, _)))
  case Amb(a, b) => det(a) ++ det(b)
}

Note that I'm using a sealed trait instead of an abstract class in order to take advantage of the compiler's ability to check exhaustivity.

It works as expected:

scala> val app = App(Var("f"), Amb(Var("x"), Amb(Var("y"), Var("z"))))
app: App = App(Var(f),Amb(Var(x),Amb(Var(y),Var(z))))

scala> det(app) foreach println
App(Var(f),Var(x))
App(Var(f),Var(y))
App(Var(f),Var(z))

If you can change the Term API, you could more or less equivalently add a def det: Stream[Term] method there.

Upvotes: 4

Mark
Mark

Reputation: 1181

Scala provides pattern matching solve these kinds of problems. A solution would look like:

def matcher(term: Term): List[Term] = {
  term match {
    case Amb(a, b) => matcher(a) ++ matcher(b)
    case App(a, b) => for { va <- matcher(a); vb <- matcher(b) } yield App(va, vb)
    case v: Var    => List(v)
  }
}

Upvotes: 5

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