CODEWITHSUNDEEP
java
user1050619
user1050619

Reputation: 20856

Issue passing a array to a variable argument character parameter

I'm creating anonymous array and passing it to a method which is declared to receive a variable argument character...

I'm wondering how the below code will run successfully, I'm passing a array of characters {'A','B','C,'D'} and the method can receive only characters...shouldn't it fail with wrong types passed? ie; character array vs characters?

public class test {


    public static void main(String[] args) {
        callme(new char[]{'A','B','C','D'});
    }

    static void callme(char... c){
        for (char ch:c){
            System.out.println(ch);
        }

        }

}

Upvotes: 0

Views: 61

Answers (2)

Peter Lawrey
Peter Lawrey

Reputation: 533492

They are the same. A char... is a char[]

You can also write

public static void main(String[] args) {
    callme('A','B','C','D');
}

static void callme(char... c){
    for (char ch : c) {
        System.out.println(ch);
    }

Upvotes: 3

Louis Wasserman
Louis Wasserman

Reputation: 198033

This will work fine. All the varargs syntax with char... actually does is that it is actually implemented as callme(char[] c), and all the callers of that method who just pass in comma-separated chars will be converted to passing in an anonymous array, exactly as you did by hand.

Upvotes: 1

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