CODEWITHSUNDEEP
pythonpython-3.x
user2821285
user2821285

Reputation: 1

Python 3.3 Beginner: Need help understand how the "and not" part of this code functions

Let's say the user enters the integer 10. I know the print(the_sum) line produces 12 because 3 and 9 are both chosen. I don't understand why it is 3 and 9 that are chosen. In the if statement line: "number % 2 and not number % 3" is where I am getting confused. I guess I just don't understand what the "and not" is doing to change that line to produce 3 and 9 to be added for the_sum. Any help would be greatly appreciated so I can move forward with more understanding.

the_max = int(input("Enter the upper limit:"))
the_sum = 0
extra = 0

for number in range(1,the_max):
    if number%2 and not number%3:
        the_sum = the_sum + number
    else:
        extra += 1 

print(the_sum) 
print(extra)

Upvotes: 0

Views: 141

Answers (3)

arshajii
arshajii

Reputation: 129537

if number%2 and not number%3:

To understand this line you first have to understand how ints are treated when used in a bool context. In a nutshell, any int that has a value of 0 is considered False and all other ints are considered True.

Now, when is n % 2 equal to 0 so as to be considered False? Well, when n is evenly divisible by 2. The same can be said for n % 3: it's False when n is evenly divisible by 3. So that if-statement can be thought of as:

If ((number is not divisible by 2) and (number is divisible by 3))

Note that since n % 3 is true for all ints not divisible by 3, not n % 3 is true for all ints that are divisible by 3.

This matches the output you see: 9 and 3 are the only two integers in the range 1 to 9 (inclusive) that satisfy this condition.

Upvotes: 3

Martijn Pieters
Martijn Pieters

Reputation: 1123360

Try out the components for 9:

>>> 9 % 2
1
>>> 9 % 3
0
>>> not 9 % 3
True
>>> 9 % 2 and not 9 % 3
True

Numeric 0 is false in a boolean context, and any other number is considered true. not 0 is therefor true.

For any other number, the combination never returns true values for both tests:

>>> 1 % 2
1
>>> 1 % 3
1
>>> not 1 % 3
False

In other words, only numbers that are not divisible by 2 but are divisible by 3 are picked.

To simplify understanding, you could explicitly test for numeric 0 instead:

if number % 2 != 0 and number % 3 == 0:

Upvotes: 1

forivall
forivall

Reputation: 9913

The modulo operator (%) will return an int, which corresponds to the remainder of division of the 2 numbers. In if statements, Python treats numbers according to their truthiness -- 0 is falsey, everything else is truthy. So this code is being a little bit too clever. I would clarify it like so:

    if number % 2 != 0 and number % 3 == 0:

Upvotes: 0

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