Dave Carpeneto
Dave Carpeneto

Reputation: 1080

How to programmatically make cocoa application active

I've got a background process that makes a transparent window appear when a hotkey is pressed:

[window makeKeyAndOrderFront:nil];
[[content animator] setAlphaValue:1.0]; // alpha was 0.0

... the window shows up fine & in front of the other windows (as I want it to), however until I manually click the window whatever application was active when the window appears remains active. I was expecting the 'makeKeyAndOrderFront' to make the application active as well, however adding a NSLog line to my -applicationWillBecomeActive shows it's not getting any active notification until the mouse click is performed.

Does anyone know how I can set my application active @ the same time I issue the -makeKeyAndOrderFront ? I need it active so that it can begin accepting keyboard input - any assistance needed :-)

Upvotes: 26

Views: 11547

Answers (3)

Ahmadreza
Ahmadreza

Reputation: 7212

Swift 4.2+ of @Arvin answer

NSRunningApplication.current.activate(options: [.activateIgnoringOtherApps, .activateAllWindows])

Upvotes: 6

Arvin
Arvin

Reputation: 2616

For 10.6 or greater

[[NSRunningApplication currentApplication] activateWithOptions:(NSApplicationActivateAllWindows | NSApplicationActivateIgnoringOtherApps)];

Upvotes: 12

Nicolas Goy
Nicolas Goy

Reputation:

Look at [[NSApplication sharedApplication] activateIgnoringOtherApps : YES];.

Upvotes: 54

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