How to remove decimal values from a value of type 'double' in Java

Question

I am invoking a method called "calculateStampDuty", which will return the amount of stamp duty to be paid on a property. The percentage calculation works fine, and returns the correct value of "15000.0". However, I want to display the value to the front end user as just "15000", so just want to remove the decimal and any preceding values thereafter. How can this be done? My code is below:

float HouseValue = 150000;
double percentageValue;

percentageValue = calculateStampDuty(10, HouseValue);

private double calculateStampDuty(int PercentageIn, double HouseValueIn){
    double test = PercentageIn * HouseValueIn / 100;
    return test;
}

I have tried the following:

• Creating a new string which will convert the double value to a string, as per below:

  String newValue = percentageValue.toString();

• I have tried using the 'valueOf' method on the String object, as per below:

  String total2 = String.valueOf(percentageValue);

However, I just cannot get a value with no decimal places. Does anyone know in this example how you would get "15000" instead of "15000.0"?

Thanks

Answer 1

This should do the trick.

System.out.println(percentageValue.split("\\.")[0]);

Answer 2

declare a double value and convert to long convert to string and formated to float the double value finally replace all the value like 123456789,0000 to 123456789

Double value = double value ;
Long longValue = value.longValue();  
String strCellValue1 = new String(longValue.toString().format("%f",value).replaceAll("\\,?0*$", ""));

Answer 3

the simple way to remove

new java.text.DecimalFormat("#").format(value)

Answer 4

    public class RemoveDecimalPoint{

         public static void main(String []args){
            System.out.println(""+ removePoint(250022005.60));
         }
 
       public static String  removePoint(double number) {        
            long x = (long) number;
            return x+"";
        }

    }

Answer 5

Use Math.Round(double);

I have used it myself. It actually rounds off the decimal places.

d = 19.82;
ans = Math.round(d);
System.out.println(ans);
// Output : 20 

d = 19.33;
ans = Math.round(d);
System.out.println(ans);
// Output : 19 

Hope it Helps :-)

Answer 6

I did this to remove the decimal places from the double value

new DecimalFormat("#").format(100.0);

The output of the above is

100

Answer 7

Double d = 1000d;
System.out.println("Normal value :"+d);
System.out.println("Without decimal points :"+d.longValue());

Answer 8

Double i = Double.parseDouble("String with double value");

Log.i(tag, "display double " + i);

try {
    NumberFormat nf = NumberFormat.getInstance();
    nf.setMaximumFractionDigits(0); // set as you need
    String myStringmax = nf.format(i);

    String result = myStringmax.replaceAll("[-+.^:,]", "");

    Double i = Double.parseDouble(result);

    int max = Integer.parseInt(result);
} catch (Exception e) {
    System.out.println("ex=" + e);
}

Answer 9

You can convert double,float variables to integer in a single line of code using explicit type casting.

float x = 3.05
int y = (int) x;
System.out.println(y);

The output will be 3

Answer 10

Alternatively, you can use the method int integerValue = (int)Math.round(double a);

Answer 11

Type casting to integer may create problem but even long type can not hold every bit of double after narrowing down to decimal places. If you know your values will never exceed Long.MAX_VALUE value, this might be a clean solution.

So use the following with the above known risk.

double mValue = 1234567890.123456;
long mStrippedValue = new Double(mValue).longValue();

Answer 12

Nice and simple. Add this snippet in whatever you're outputting to:

String.format("%.0f", percentageValue)

Answer 13

Try this you will get a string from the format method.

DecimalFormat df = new DecimalFormat("##0");

df.format((Math.round(doubleValue * 100.0) / 100.0));

Answer 14

The solution is by using DecimalFormat class. This class provides a lot of functionality to format a number.
To get a double value as string with no decimals use the code below.

DecimalFormat decimalFormat = new DecimalFormat(".");
decimalFormat.setGroupingUsed(false);
decimalFormat.setDecimalSeparatorAlwaysShown(false);

String year = decimalFormat.format(32024.2345D);

Answer 15

String truncatedValue = String.format("%f", percentageValue).split("\\.")[0]; solves the purpose

The problem is two fold-

1. To retain the integral (mathematical integer) part of the double. Hence can't typecast (int) percentageValue
2. Truncate (and not round) the decimal part. Hence can't use String.format("%.0f", percentageValue) or new java.text.DecimalFormat("#").format(percentageValue) as both of these round the decimal part.

Answer 16

I would try this:

String numWihoutDecimal = String.valueOf(percentageValue).split("\\.")[0];

I've tested this and it works so then it's just convert from this string to whatever type of number or whatever variable you want. You could do something like this.

int num = Integer.parseInt(String.valueOf(percentageValue).split("\\.")[0]);

Answer 17

You could use

String newValue = Integer.toString((int)percentageValue);

Or

String newValue = Double.toString(Math.floor(percentageValue));

Answer 18

Try:

String newValue = String.format("%d", (int)d);

Answer 19

You can use DecimalFormat, but please also note that it is not a good idea to use double in these situations, rather use BigDecimal

Answer 20

You can convert the double value into a int value. int x = (int) y where y is your double variable. Then, printing x does not give decimal places (15000 instead of 15000.0).

Answer 21

With a cast. You're basically telling the compiler "I know that I'll lose information with this, but it's okay". And then you convert the casted integer into a string to display it.

String newValue = ((int) percentageValue).toString();