CODEWITHSUNDEEP
collectionsunderscore.jslodash
Christer
Christer

Reputation: 41

How can I iterate through a collection with underscore.js/lodash.js

Minor problem. I have the collection

var allnames = {
    'names': 
     [
         { 'name': [ {'surname': 'moe'}, {'nickname': 'moose' } ] },
         { 'name': [ {'surname':'larry'}, {'nickname': 'lark' } ] }
     ]
};

and want to access/fetch each 'surname' and 'nickname'.

I have tried different options without any luck (e.g. _.each/_.map).

Is there anyone having experience in this area?

Upvotes: 0

Views: 2359

Answers (2)

Gruff Bunny
Gruff Bunny

Reputation: 27976

This snippet will turn the structure you have there into something that's easier to work with:

 var names = _.map( allnames.names, function(n){
    // n is an array with each object having one property; either a surname or a nickname
    return _.reduce(n.name, function(memo,part){ return _.extend(memo,part); }, {})
 });

Here names will be an array of objects with each object having a surname and a nickname:

[ { surname: 'moe', nickname: 'moose' }, { surname: 'larry', nickname: 'lark' } ]

Once you have that structure it's easy to manipulate that array to extract what you want e.g. get all the surnames:

var surnames = _.pluck(names, 'surname');
var nicknames = _.pluck(names, 'nickname');

Upvotes: 5

Christer
Christer

Reputation: 41

I eventually found a solution, which covers what I was striving at

var allnames = {
    'names': 
     [
        { 'name': [ {'surname': 'moe'}, {'nickname': 'moose' } ] },
        { 'name': [ {'surname': 'larry'}, {'nickname': 'lark' } ] }
     ]
};

var surnames = [];
var nicknames = [];

function nameproc(myobj) 
{ 
    if ( myobj.surname ) 
    {
        surnames.push(myobj.surname);
        return myobj.surname
    }
    if( myobj.nickname) 
    {
        nicknames.push(myobj.nickname);
        return myobj.nickname;
    }
}

_.each(allnames.names, function(myobj) 
{ 
    _.each(myobj, function(nameobj) 
    {
        var nameobj = _.each(nameobj,nameproc);
    });
});

// Print out the surnames and nicknames

console.log(surnames);
console.log(nicknames);

Upvotes: 0

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