Reputation: 685
Can anyone help me to find out what can be the issue with this program.
In the onCreate()
method the findViewById()
returns null for all ids and this causes a null pointer exception later. I can not figure out why the findViewById()
can not find the view. Any suggestions?
This is the main code:
public class MainActivity extends Activity {
ViewPager pager;
MyPagerAdapter adapter;
LinearLayout layout1, layout2, layout3;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
layout1 = (LinearLayout) findViewById(R.id.first_View);
layout2 = (LinearLayout) findViewById(R.id.second_View);
layout3 = (LinearLayout) findViewById(R.id.third_View);
adapter = new MyPagerAdapter();
pager = (ViewPager) findViewById(R.id.main_pager);
pager.setAdapter(adapter);
}
private class MyPagerAdapter extends PagerAdapter
{
@Override
public int getCount() {
return 3;
}
@Override
public Object instantiateItem(ViewGroup collection, int position) {
LinearLayout l = null;
if (position == 0 )
{
l = layout1;
}
if (position == 1)
{
l = layout2;
}
if (position == 2)
{
l = layout3;
}
collection.addView(l, position);
return l;
}
@Override
public boolean isViewFromObject(View view, Object object) {
return (view==object);
}
@Override
public void destroyItem(ViewGroup collection, int position, Object view) {
collection.removeView((View) view);
}
}
}
And the related XML files:
activity_main layout:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:background="#a4c639">
<android.support.v4.view.ViewPager
android:layout_width="match_parent"
android:layout_height="match_parent"
android:id="@+id/main_pager"/>
</LinearLayout>
activity_first layout:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:id="@+id/first_View">
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/hello_world" />
<Button
android:id="@+id/button1"
style="?android:attr/buttonStyleSmall"
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Button" />
</LinearLayout>
activity_second layout:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:id="@+id/second_View">
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/hello_world" />
</LinearLayout>
And the activity_third layout:
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:id="@+id/third_View">
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/hello_world" />
</LinearLayout>
Upvotes: 59
Views: 63600
Reputation: 9
Use the adaptor, to inflate the layout, and based on the position you can search for the view.
override fun instantiateItem(collection: ViewGroup, position: Int) : ViewGroup {
val inflater = LayoutInflater.from(mContext)
val layout = inflater.inflate(mData[position], collection, false) as ViewGroup
if(position == your_position) {
val nameOfField: TextView = layout.findViewById(R.id.item_id)
}
Upvotes: 0
Reputation: 187
This problem is also generated when you are having same name of many components in XML file. Even if they are different layout files you should give every element a unique name. This error occur because you are having a XML element with the same name in another layout file and android studio is trying to access that and showing this error
Upvotes: -1
Reputation: 5971
findViewById()
returns a View if it exists in the layout you provided in setContentView()
, otherwise it returns null and that's what happening to you. Note that if you don't setContentView()
, and don't have a valid view to findViewById()
on, findViewById()
will always return null until you call setContentView()
.
This also means variables in the top-level trigger an NPE, because they're called before onCreate()
, and by extension, before setContentView()
. See also the activity lifecycle
Example if you setContentView(R.layout.activity_first);
and then call findViewById(R.id.first_View);
it will return a View which is your layout.
But if you call findViewById(R.id.second_View);
before setContentView()
, it will return null
since there is not a view in your activity_first.xml
layout called @+id/second_View
.
Upvotes: 92
Reputation: 1710
In my case, it was a stupid mistake on my part. I had written code in the OnCreate method but it was above the setContentView
line of code. Once I moved my code below this line the application started working fine.
setContentView(R.layout.activity_main);
Upvotes: 1
Reputation: 192023
Emphasis added
For those cases within an Activity class.
Activity.findViewById(int id)
Finds a view that was identified by the
id
attribute from the XML that was processed inonCreate(Bundle)
.
Otherwise, such as an Fragment, Adapter, a View
from a LayoutInflater
, etc.
View.findViewById(int id)
Look for a child view with the given
id
. If this view has the given id, return this view.
Either case,
Returns
The view if found ornull
otherwise.
Now, re-check your XML files. Make sure you put the right value into setContentView
or inflater.inflate
.
In the case of an Activity, call findViewById
after setContentView
.
Then, make sure there is a View you are looking for with android:id="@+id/..."
in that layout. Make sure the +
is at @+id
, which will add the resource to the R.id
values to ensure you can find it from Java.
Upvotes: 3
Reputation: 11
The findViewById
method must find what is in the layout (which you called in the setContentView
)
Upvotes: 0
Reputation: 940
In Android, findViewById(R.id.some_id)
works when you are finding view in the layout set.
That is, if you have set a layout say:
setContentView(R.layout.my_layout);
Views can be found only in this layout (my_layout).
In your code layout1
, layout2
, layout3
all are three different layouts and they are not set to the activity.
Upvotes: 0
Reputation:
I have gotten this error today and it was so simple to clear, that I "facepalmed".
Just try to add the UI element to your layout xml File in your res/layout-port directory!!!
Upvotes: 0
Reputation: 3597
Sometimes you need clean your project in Eclipse (Project - Clean..).
Upvotes: 2
Reputation: 16536
The views you're trying to get are not defined in your activity_main
layout. You need to programmatically inflate the views you're trying to add to the pager.-
@Override
public Object instantiateItem(ViewGroup collection, int position) {
LinearLayout l = null;
if (position == 0) {
l = (LinearLayout) View.inflate(this, R.layout.activity_first, null);
}
if (position == 1) {
l = (LinearLayout) View.inflate(this, R.layout.activity_second, null);
}
if (position == 2) {
l = (LinearLayout) View.inflate(this, R.layout.activity_third, null);
}
collection.addView(l, position);
return l;
}
Upvotes: 2
Reputation: 41
What @Warlock said above is right , you should initial LinearLayout layout1, layout2, layout3 by the right way:
LinearLayout layout1 = (LinearLayout) View.inflate(this, R.layout.first_View, null);
LinearLayout layout2 = (LinearLayout) View.inflate(this, R.layout.second_View, null);
LinearLayout layout3 = (LinearLayout) View.inflate(this, R.layout.third, null);
wish my advise help you
Upvotes: 0
Reputation: 2665
add those views to the pager adapter before accessing them.
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
adapter = new MyPagerAdapter();
pager = (ViewPager) findViewById(R.id.main_pager);
pager.setAdapter(adapter);
layout1 = (LinearLayout) findViewById(R.id.first_View);
layout2 = (LinearLayout) findViewById(R.id.second_View);
layout3 = (LinearLayout) findViewById(R.id.third_View);
}
in the pager adapter:
public Object instantiateItem(View collection, int position) {
if(position == 0){
View layout = inflater.inflate(R.layout.activity_first, null);
((ViewPager) collection).addView(layout);
return layout;
}
... and so forth.
}
from here you can access them via findViewById.
Upvotes: 1