Reputation: 696
My problem is that I need to get a div class inside a div class inside a div class and the are 4 instances of the classes with the same name but different data... I can currently get the first div class inside the div class but i need to be able to access other elements within it aswell......for example:
docTide = Jsoup.connect("http://www.mhpa.co.uk/search-tide-times/").timeout(600000).get();
Elements tideTableRows = docTide.select("div.tide_row.odd");
Element firstDiv = tideTableRows.first();
Element secondDiv = tideTableRows.get(1);
System.out.println("This is the first div: " + firstDiv.text());
System.out.println("This is the second div: " + secondDiv.text());
but this is the structure of the webpage where there are 2 repeats and I need to access each of them e.g:
<div class="tide_row odd">
<div class="time">00:57</div>
<div class="height_m">4.9</div>
<div class="height_f">16,1</div>
<div class="range_m">1.9</div>
<div class="range_f">6,3</div>
</div>
<div class="tide_row even">
<div class="time">07:23</div>
<div class="height_m">2.9</div>
<div class="height_f">9,6</div>
<div class="range_m">2</div>
<div class="range_f">6,7</div>
</div>
<div class="tide_row odd">
<div class="time">13:46</div>
<div class="height_m">5.1</div>
<div class="height_f">16,9</div>
<div class="range_m">2.2</div>
<div class="range_f">7,3</div>
</div>
<div class="tide_row even">
<div class="time">20:23</div>
<div class="height_m">2.8</div>
<div class="height_f">9,2</div>
<div class="range_m">2.3</div>
<div class="range_f">7,7</div>
</div>
So basically it has nested classes in separate classes with the same name, how can I construct the correct syntax to return the data from the classes separately? This is quite hard to explain!
Edit: This is how I managed to extract the information from the nested classes:
docTide = Jsoup.connect("http://www.mhpa.co.uk/search-tide-times/").timeout(600000).get();
Elements tideTimeOdd = docTide.select("div.tide_row.odd div:eq(0)");
Elements tideTimeEven = docTide.select("div.tide_row.even div:eq(0)");
Elements tideHightOdd = docTide.select("div.tide_row.odd div:eq(2)");
Elements tideHightEven = docTide.select("div.tide_row.even div:eq(2)");
Element firstTideTime = tideTimeOdd.first();
Element secondTideTime = tideTimeEven.first();
Element thirdTideTime = tideTimeOdd.get(1);
Element fourthTideTime = tideTimeEven.get(1);
Element firstTideHight = tideHightOdd.first();
Element secondTideHight = tideHightEven.first();
Element thirdTideHight = tideHightOdd.get(1);
Element fourthTideHight = tideHightEven.get(1);
Upvotes: 0
Views: 285
Reputation: 731
It would work fine by just doing:
docTide = Jsoup.connect("http://www.mhpa.co.uk/search-tide-times/").timeout(600000).get();
Elements tideTableRows = docTide.select("div[class=tide_row odd]");
Element firstDiv += tideTableRows.select("div[class=time]");
Element secondDiv += tideTableRows.select("div[class=height]");
You should try to access elements by id if you can. It makes your code a lot simpler and if you have 50 headers in the same container, as an example, this way you don't have to count them all.
Seperate elements:
docTide = Jsoup.connect("http://www.mhpa.co.uk/search-tide-times/").timeout(600000).get();
Element tideTableRows = docTide.select("div[class=tide_row odd]").first();
Element firstDiv1 = tideTableRows.select("div[class=time]");
Element secondDiv1 = tideTableRows.select("div[class=height]");
tideTableRows2 = docTide.select("div[class=tide_row odd]").second();
Element firstDiv2 = tideTableRows.select("div[class=time]");
Element secondDiv2 = tideTableRows.select("div[class=height]");
Upvotes: 1
Reputation: 11712
You can try this:
docTide = Jsoup.connect("http://www.mhpa.co.uk/search-tide-times/").timeout(600000).get();
Elements tideTableRows = docTide.select("div.tide_row");
for (Element tideTableRow : tideTableRows){
if (tideTableRow.hasClass("odd")){
//do the odd stuff...
}
Elements innerDivs = tideTableRows.select("div");
for (Element innerDiv : innerDivs){
//do whatever you need
}
}
Note: The code is not tested.
Update: I showed you how to access the odd rows only... From there you should be able to get the rest by yourself I hope.
Upvotes: 1