CODEWITHSUNDEEP
c
Sammie Johanson
Sammie Johanson

Reputation: 11

Ascii Conversion Program; printing error

I have been working on this program in C, and I don't understand why it is printing beyond the range that parameters state. here is the program, can anyone help me? Also, how do i get the input to reject numbers that arent in specified range? Thanks in advance!

#include <stdlib.h>
#include <stdio.h>
#define LEN 64

int main(){

    char line[LEN];
    printf("Enter a #, 32-127: ");
    fgets(line,LEN,stdin);
    int i = atoi(line);

    printf("Enter a #, %d-127: ",i);
    fgets(line,LEN,stdin);
    int j = atoi(line);

    for(i;j;i++)
        printf("ASCII value of character %d: %c\n",i,i);

    return(EXIT_SUCCESS);
    }

Upvotes: 1

Views: 96

Answers (2)

Cacho Santa
Cacho Santa

Reputation: 6914

You need to understand clearly what is this line doing:

for(i;j;i++)

Read more about the for-statement here

for (initialization; condition; increment){
       body
}

In your code, j is your condition. In C, zero == false and different from zero is true. Consequently, j never becomes zero, so the loop becomes an infinite loop.

Try to explain a little more what are you trying to achieve with the for-statement so we can help you better.

Upvotes: 1

OldProgrammer
OldProgrammer

Reputation: 12169

Your "for" loop is incorrect. Instead, try something like:

while ( i <= j ) {
   printf("ASCII value of character %d: %c\n",i,i);
   i++;
}

or

   for ( int idx = i; idx <=j; idx++) {
     printf("ASCII value of character %d: %c\n",idx,idx);
    }

For validation, just do an "if" statement, and compare the input values to whatever your validation range would be. Leave that to you.

Upvotes: 1

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