CODEWITHSUNDEEP
javaandroid
T_V
T_V

Reputation: 17580

java.lang.StackOverflowError?

I am sure that, this ques code must be asked in this site. But I am not able to search, This is basic ques, but I am not getting it because of my poor basic concept-

public class A {

A obj = new A();

public static void main(String arg[])
{
    A ob = new A();
}
}

It is giving java.lang.StackOverflowError,Why?

Upvotes: 0

Views: 520

Answers (4)

AppX
AppX

Reputation: 528

Every time you create an object A it will create another object A that will create another object A...

Upvotes: 5

blackpanther
blackpanther

Reputation: 11486

StackOverflow errors occur because there is a very deep recursion within the application. When you instantiate A, you also call the same constructor to create another instance of A and hence, you have a recursive tree and thus causing the stack overflow error.

Hence, the real problem is deep recursive calls to instantiate A.

Upvotes: 1

Viktor Ozerov
Viktor Ozerov

Reputation: 326

When you create object of type A, you're creating new object of type A, which creates new object of type A etc.

Upvotes: 0

Rohit Jain
Rohit Jain

Reputation: 213223

Your class is essentially equivalent to:

public class A {

    A obj;
    public A() {
        obj = new A();
    }  

    public static void main(String arg[]) {
        A ob = new A();
    }
}

Now you see how you got that error? Everytime you create an instance of A, the constructor get's called, which again invokes itself to create another instance, and this goes on filling up the stack till it overflows.

Upvotes: 5

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