CODEWITHSUNDEEP
androidandroid-intentandroid-service
firetrap
firetrap

Reputation: 2005

Unable to start service Intent: not found

I've the same issue described here but i can't understand whats wrong.

My issue is: Unable to start service Intent { act=.connections.MoodyService } U=0: not found

EDIT I've changed my package from connections to service in the source code, sorry for the confusion

My manifest.xml

<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.example.moody"
android:installLocation="auto"
android:versionCode="0"
android:versionName="0.6.7 alpha" >

<uses-sdk
    android:maxSdkVersion="18"
    android:minSdkVersion="14"
    android:targetSdkVersion="17" />

<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE" />

<application
    android:allowBackup="true"
    android:allowClearUserData="true"
    android:icon="@drawable/ic_launcher"
    android:label="@string/app_name"
    android:theme="@style/AppTheme" >
    <activity
        android:name="activities.MainActivity"
        android:label="@string/app_name" >
    </activity>
    <activity
        android:name="activities.Menu_esq"
        android:label="@string/title_activity_menu_esq" >
    </activity>
    <activity
        android:name="activities.BaseActivity"
        android:label="@string/title_activity_base" >
    </activity>
    <activity
        android:name="activities.MainView"
        android:label="@string/title_activity_main_view" >
    </activity>
    <activity
        android:name="activities.LoginActivity"
        android:label="@string/app_name"
        android:noHistory="true"
        android:windowSoftInputMode="adjustResize|stateVisible" >
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />

            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
    </activity>
    <activity
        android:name="com.example.moody.LeftActivity"
        android:label="@string/title_activity_left" >
    </activity>
    <activity
        android:name="com.example.moody.RightActivity"
        android:label="@string/title_activity_right" >
    </activity>
    <activity
        android:name="activities.UserDetailsActivity"
        android:label="@string/title_activity_user_details" >
    </activity>
    <activity
        android:name="fragments.TopicsPreview"
        android:label="@string/title_activity_copy_of_topics_preview" >
    </activity>
    <activity android:name="activities.Loading" >
    </activity>

    <service
        android:name=".service.MoodyService"
        android:icon="@drawable/ic_launcher"
        android:label="@string/moody_service" >
    </service>
</application>

service is the package and MoodyService is the class name

My service class

public class MoodyService extends Service {

public MoodyService() {
    // TODO Auto-generated constructor stub
}

private boolean isRunning = false;
Object getContent;

@Override
public IBinder onBind(Intent intent) {
    // TODO Auto-generated method stub

    return null;
}

@Override
public void onCreate() {
    super.onCreate();
}

@Override
public int onStartCommand(Intent intent, int flags, int startId) {
    super.onStartCommand(intent, flags, startId);

    // Announcement about starting
    Toast.makeText(this, "Starting the Demo Service", Toast.LENGTH_SHORT)
            .show();

    // Start a Background thread
    isRunning = true;
    Thread backgroundThread = new Thread(new BackgroundThread());
    backgroundThread.start();

    // We want this service to continue running until it is explicitly
    // stopped, so return sticky.
    return START_STICKY;
}

@Override
public void onDestroy() {
    super.onDestroy();

    // Stop the Background thread
    isRunning = false;

    // Announcement about stopping
    Toast.makeText(this, "Stopping the Demo Service", Toast.LENGTH_SHORT)
            .show();
}

private class BackgroundThread implements Runnable {
    int counter = 0;

    public void run() {
        try {
            counter = 0;
            while (isRunning) {
                System.out.println("" + counter++);
                new Contents().getAll(getResources(),
                        getApplicationContext());
                Thread.currentThread().sleep(5000);
            }

            System.out.println("Background Thread is finished.........");
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}

And in my main Intent.

Intent start = new Intent(".service.MoodyService");
        this.startService(start);

and also tried

Intent intent = new Intent(this, MoodyService.class);
        this.startService(intent);

and tried with the full path

<service
    android:name="com.example.moody.service.MoodyService"
    android:icon="@drawable/ic_launcher"
    android:label="@string/moody_service" >

Upvotes: 43

Views: 89503

Answers (9)

Galahad
Galahad

Reputation: 373

For those who get this error despite the fact that the service is declared in the manifest and the package name is correct, check that your application is not in background.

From Android O, apps are not allowed to start background services from the background. See note here: https://developer.android.com/reference/android/content/Context#startService(android.content.Intent).

Use startForegroundService() instead in this case, but keep in mind that apps are not allowed to start foreground services from the background since Android S.

Upvotes: 0

Anu
Anu

Reputation: 109

Make sure you have declared your service in the manifest file.

<service  
      android:name=".MyService"  
      android:enabled="true" >
</service>

and try writing getApplicationContext() instead of "this" keyword 

startService(new Intent(getApplicationContext(), MoodyService.class));

Upvotes: 10

Habil
Habil

Reputation: 540

my service is in "service" package and my manifest service enrty like this;

     <service
        android:name="service.TimerService"
        android:exported="false" >
    </service>

Upvotes: 1

Francisco Corrales Morales
Francisco Corrales Morales

Reputation: 3834

The service must be also be included in the Manifest:

<service android:name="com.x.x.serviceclass"></service>

Upvotes: 23

Dominik Mayrhofer
Dominik Mayrhofer

Reputation: 491

Did you try to use the android:name that you specified in the Manifest?

Android Manifest:

<service 
             android:enabled="true" 
             android:name="UploadService" />

The call would be sth like this:

Intent intent = new Intent("UploadService");

Upvotes: -3

firetrap
firetrap

Reputation: 2005

Solved

I deleted the period in the beginning of the package name in the manifest and it worked, in another words:

This doesn't work:

.yourPackage.YourClass

But this does work:

 yourPackage.YourClass

And in the main:

Intent intent = new Intent(this, MoodyService.class);
        this.startService(intent);

But it goes against what is written in the documentation:

android:name The name of the Service subclass that implements the service. This should be a fully qualified class name (such as, "com.example.project.RoomService"). However, as a shorthand, if the first character of the name is a period (for example, ".RoomService"), it is appended to the package name specified in the element. Once you publish your application, you should not change this name (unless you've set android:exported="false").

There is no default. The name must be specified.

Upvotes: 30

Shakeeb Ayaz
Shakeeb Ayaz

Reputation: 6096

I think in manifest package name for service is wrong as you said your package name is connections so it should be like this

  android:name ="connections.MoodyService"

or

  android:name="com.example.moody.connections.MoodyService"

to invoke service do

  Intent intent = new Intent(this, MoodyService.class);
    this.startService(intent);

Upvotes: 3

sam
sam

Reputation: 2820

I don't know why you are using that package-like name for your service name, but why don't you use class name for starting the service?

Intent intent = new Intent(context, YourService.class);
context.startService(intent);

Upvotes: 4

cYrixmorten
cYrixmorten

Reputation: 7108

Did you create an empty constructor in the service?

If not, try that.

Also uncertain if you can use the Intent like that. You could try the 'new Inten(this, MoodyService.class)' construction.

Upvotes: 0

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