CODEWITHSUNDEEP
xmlxsltxslt-1.0xslt-2.0
kumar
kumar

Reputation: 389

how to get the value of other child node element

I am trying to get a the value <abc-value>abc</abc-value> of other child node elment from current node.

Example:

<root>
  <child1>
     <abc-value>abc</abc-value>
  </child>
  <child2>
     <attribute name=def>def</def-value>
  </child2>
</root>

XSL:

<xsl:template name="child2" match="attribute">
   child1 value is: <xsl:value-of select="../abc-value"/>
   child2 value is: <xsl:value-of select="current()"/>
</xsl:template>

All i am trying to do is, from child2 template match, I am calling the value of child1 element <abc-value>abc</abc-value>.

Exptected out:

Child1 value is: abc

Child2 value is: def

Upvotes: 0

Views: 2887

Answers (1)

LarsH
LarsH

Reputation: 27996

<xsl:template name="child2" match="attribute">
   child1 value is: <xsl:value-of select="../../child1/abc-value" />
   child2 value is: <xsl:value-of select="." />
</xsl:template>

Update: based on the edit to your question:

  • The template now matches the <attribute> element.
  • Since the current node for the template (the <attribute> element) is deeper than before, the select expression for the child1 value is changed to use an additional ../.

Upvotes: 3

Related Questions