CODEWITHSUNDEEP
javaarraylistjava.util.scanner
user2809437
user2809437

Reputation: 492

Adding parameters to arraylist with Java

I am testing my college class and when the user types in "add" it adds a new student to the arraylist in the college class.

   Scanner myInput=new Scanner (System.in);
   String information=myInput.next(); //I know this is incorrect not sure what else to do
    directory.addStudent(information);

here the directory is the object of the arraylist containing students. the addStudent method is in the College class, and looks like this:

  public void addStudent (String studentName, long studentID, String address) {
        Student newStu= new Student( studentname, studentID, address);
        collegeList.add(newStu); //here collegeList is the name of the arraylist in College class
   }

anyways my question seems simple but can't figure it out. I want to know how to split the information so that it can satisfy the parameters in addStudent method...As you can see information will be a String but I want studentID to be a long not a string what can I do?

Upvotes: 0

Views: 3756

Answers (3)

Sohil Omer
Sohil Omer

Reputation: 1181

You can use split() method to break your information

What you have to do is 

String str = new String(information);
String[] s = str.split(" ", 3);

i am splitting on the space basis , second argument 3 means you have to break into 3 strings i.e name,id,address

after this you can get name via s[0] , id via s[1] and address via s[2] so you can pass easily over addStudent() method . but you need to convert the values according to the arguments of addStudent() method

Upvotes: 0

Ashish
Ashish

Reputation: 14707

Try this:

import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;
public class StudentMain {
    private static List<Student> collegeList = new ArrayList<Student> (); 
    public static void main(String...args)throws Throwable {
         String s= null; String name=null; long id=0L; String address = null; 
        System.out.print("What do you want to do today, press q to quit : ");
        Scanner sc = new Scanner(System.in);
        do{
        try{    
                s = sc.next();
                if(s.equalsIgnoreCase("add")){
                    System.out.print("Enter the name of student:  ");
                    name = sc.next();
                    System.out.print("Enter the Id of student : " );
                    id=sc.nextLong();
                    System.out.print("Enter address of student:  ");
                    address = sc.next();
                    addStudent(name,id,address);
                }
        }catch(NumberFormatException e){
            if(!s.equalsIgnoreCase("q"))
                System.out.println("Please enter q to quit else try again ==> ");
            }
        }while(!s.equalsIgnoreCase("q"));
    sc.close();
    }
    private static void addStudent(String name, long id, String address) {
        // TODO Auto-generated method stub
        Student newStu = new Student(name,id,address);
        collegeList.add(newStu);        
    }

}

class Student{
    String name;
    Long id;
    String address;

    Student(String name,Long id,String address){
    this.name= name;
    this.id = id;
    this.address=address;
    }
}

Upvotes: 0

Mohayemin
Mohayemin

Reputation: 3870

Splitting the string after reading is not necessary. You can read delimited string using Scanner.

I assume your inputs are separated by whitespace. If so, you need to do this:

    String name = myInput.next();
    long id = myInput.nextLong();
    String address = myInput.next();
    dictionary.add(name, id, address);

Upvotes: 2

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