CODEWITHSUNDEEP
javascriptphpjson
PHP_USER1
PHP_USER1

Reputation: 628

passing information via javascript using php

<!DOCTYPE html>
<html>
<head>
<link rel="stylesheet" href="css/style.css"/>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/swfobject/2.2/swfobject.js"></script>
<script src="./js/jquery.js"></script>
<script src="./js/laddubox.js"></script>
<script src="./js/pop.js"></script>
<script src="./js/jquery.js"></script>
<script type="text/javascript">
    var sbs = {
         'url' : '<?="./gearedup-pics/"?>',
        'logged' : '<?=$notregister?>',
        'userid' : '<?= $id ?>',
        'father' : '<?= $father ?>' ,
        'mother'  : '<?= $mother ?>',
        'kid'  : "<?= $kid ?>"
        };
</script>
<title><?=$title?></title>
</head>

I am sending information via javascript using php but $kid ,$mother and $father are in array format . So its showing me an error.

Notice: Array to string conversion in C:\xampp\htdocs\sbs\sbs\html\meta.php on line 19
Array' ,

Upvotes: 0

Views: 53

Answers (1)

ComFreek
ComFreek

Reputation: 29424

<?= converts the variable to a string and outputs it. Implicitly converting arrays to strings results in a notice (not an error).

I advise you to use json_encode():

<?php
$data = array(
  'url'    => './gearedup-pics/',
  'logged' => $notregister,
  'userid' => $id,
  'father' => $father,
  'mother' => $mother,
  'kid'    => $kid
);
?>
var sbs = <?php echo json_encode($data); ?>;

Upvotes: 5

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