Axis
Axis

Reputation: 37

PHP link to include header

I have php reading a text file that contains all the names of images in a directory, it then strips the file extension and displays the file name without the .jpg extension as a link to let the user click on then name, what I am looking for is a easy way to have the link that is clicked be transferred to a variable or find a easier solution so the link once it is clicks opens a page that contains the default header and the image they selected without making hundreds of HTML files for each image in the directory. my code is below I am a newbie at PHP so forgive my lack of knowledge.

thank you in advance. also I would like a apple device to read this so I want to say away from java script.

    <html>
  <head>
    <title>Pictures</title>
  </head>
  <body>
    <p>
    <?php

// create an array to set page-level variables
$page = array();

$page['title'] = ' PHP';

/* once the file is imported, the variables set above will become available to it */

// include the page header

include('header.php');

?>
<center>


      <?php
      // loads page links
 $x="0";

// readfile

// set file to read


$file = '\filelist.txt' or die('Could not open file!');

// read file into array

$data = file($file) or die('Could not read file!');

// loop through array and print each line

foreach ($data as $line) {

$page[$x]=$line;     
    $x++;

}

$x--;

for ($i = 0; $i <= $x; $i++)
 {
$str=strlen($page[$i]);
$str=bcsub($str,6);
$strr=substr($page[$i],0,$str);
$link[$i]=  "<a href=".$page[$i]."jpg>".$strr."</a>";

echo  "<td>".$link[$i]."<br/"; 

}

      ?>
      </P></center>
      <?php

// include the page footer

include('/footer.php');

?>
  </body>
</html>

Upvotes: 0

Views: 249

Answers (1)

Mattt
Mattt

Reputation: 1779

add the filename to the url that you want to use as a landing page, and catch it using $_GET to build the link.

<a href='landingpage.php?file=<?php echo $filename; ?>'><?php echo $filename; ?></a>

Then for the image link on the landing page

<img src='path/to/file/<?php echo $_GET['file'] ?>.jpg' />

Upvotes: 2

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