CODEWITHSUNDEEP
c++
calf
calf

Reputation: 881

Count the frequency of a specific character in a text input

int main()
{
  char sentence;
  int count;

  cout << "Enter sentence: ";
  cin >> sentence;

  count = 0;
  while ( sentence == 'b' || 'B' ) {
    count++;
  }

  cout << "Number of b's: " << count * 1 << endl;

  return 0;
}

The counting must also stop at all punctuation. I can't seem to get it to give me the correct count.

Upvotes: 2

Views: 4632

Answers (4)

MooseBoys
MooseBoys

Reputation: 6793

#include <iostream>
using namespace std;
int main()
{
    char c;
    int n = 0;
    cout << "Enter sentence: ";
    while (cin >> c && !ispunct(c)) if (tolower(c) == 'b') n++;
    cout << "Number of b's: " << n << endl;
    return 0;
}

Example:

Enter sentence: Two B or not two b, that is the question Bb.

Number of b's: 2

Upvotes: 0

Thomas Matthews
Thomas Matthews

Reputation: 57698

It's your while loop. The variable sentence is not changed inside the loop, so the loop may execute forever.

You may want to use std::string for a sentence and char for a character in the sentence.

Edit 1: Example

char letter;
cout << "Enter a sentence:\n";
while (cin >> letter)
{
  // Check for sentence termination characters.
  if ((letter == '\n') || (letter == '\r') || (letter == '.'))
  {
    break; // terminate the input loop.
  }
  // Put your letter processing code here.
} // End of while loop.

Upvotes: 2

Zaur
Zaur

Reputation: 43

#include <string>

Use string. string sentence; And create a for long as: 

for(int i=0; i<sentence.length(); i++)
if(sentence[i] == b || B) count ++;

So simple ;) Good luck ;)

EDIT 1:
If you will only use while:

int count = sentence.length();
int count2 = 0;
while(count != 0)
{
if(sentence[count] == b||B) count2++
count--;
}

Good luck ;)

Upvotes: 0

Enrico Granata
Enrico Granata

Reputation: 3329

There are a couple suspicious points in your program:

  char sentence;
  cin >> sentence;

This looks like it would only be reading one character. You might want to getline() and save user input in a std::string

As for

  while ( sentence == b || B ) {

This wouldn’t even compile since b and B are undefined. Maybe it should be

  if ( cur_byte == ‘b' || cur_byte == ‘B’ )
     count++

where cur_byte is some properly maintained iterator inside your string

Upvotes: 0

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