CODEWITHSUNDEEP
linuxshellunixscripting
Stunner
Stunner

Reputation: 1121

Get the number of days since file is last modified

I want to get the number of days since file last modified date to today's date.

I use this $ ls -l uname.txt | awk '{print $6 , "", $7}' but it gives me the last modified date. I want to know the number of days from a last modified date to today's date.

Any way to do this?

Upvotes: 7

Views: 4465

Answers (3)

Mark Fox
Mark Fox

Reputation: 8924

You could wrap up the differences of GNU and BSD stat with some BASH math and basic readable API:

since_last_modified() {
   local modified
   local now=$(date +%s)
   local period=$2

   stat -f %m $1 > /dev/null 2>&1 && modified=$(stat -f %m $1) # BSD stat
   stat -c %Y $1 > /dev/null 2>&1 && modified=$(stat -c %Y $1) # GNU stat

   case $period in
        day|days)    period=86400 ;; # 1 day in seconds
       hour|hours)   period=1440  ;; # 1 hour in seconds
     minute|minutes) period=60    ;; # 1 minute in seconds
           *)        period=      ;; # default to seconds
   esac

   if [[ $period > 0 ]]; then
      echo "$(( (now - modified) / period ))"
   else
      echo "$(( now - modified ))"
   fi
}

Basic usage of seconds since last modification:

since_last_modified uname.txt

or minutes saved to a variable

minutes_since=$(since_last_modified uname.txt minutes)

Upvotes: 1

Jon Lin
Jon Lin

Reputation: 143856

Try creating a script:

#!/bin/bash

ftime=`stat -c %Y uname.txt`
ctime=`date +%s`
diff=$(( (ctime - ftime) / 86400 ))
echo $diff

Upvotes: 2

user4815162342
user4815162342

Reputation: 154846

Instead of using ls, you can use date -r to tell you the modification date of the file. In addition to that, date's %s specifier, which formats the date in seconds since the epoch, is useful for calculations. Combining the two easily results in the desired number of days:

mod=$(date -r uname.txt +%s)
now=$(date +%s)          
days=$(expr \( $now - $mod \) / 86400)
echo $days

Upvotes: 10

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