A Super Awesome
A Super Awesome

Reputation: 93

Access object property in array of objects

I have this set

var data = [
    {"outlet_name":"Easy Lane Supermart","20130102_20130108":"0"},
    {"outlet_name":"Eunilaine Foodmart Kalayaan","20130102_20130108":"0"},
    {"outlet_name":"PUREGOLD PRICE CLUB, INC - VISAYAS","20130102_20130108":"0"}
];

$.each(data, function (i, item) {
    $.each(item, function (k,v) {
        $('#result').append(k,v);
    });
});

How can I make it only view all the values of outlet_name without using the item.outlet_name?

Upvotes: 5

Views: 36216

Answers (3)

VIJAYABAL DHANAPAL
VIJAYABAL DHANAPAL

Reputation: 564

This will provide exact answer...

var data = [
    {"outlet_name":"Easy Lane Supermart","20130102_20130108":"0"},
    {"outlet_name":"Eunilaine Foodmart Kalayaan","20130102_20130108":"0"},
    {"outlet_name":"PUREGOLD PRICE CLUB, INC - VISAYAS","20130102_20130108":"0"}
];
for(i=0;i<data.length;i++){
	for(var x in data[i]){
	    console.log(x + " => " + data[i][x]);
	}
}

Upvotes: 2

Leonardo Wildt
Leonardo Wildt

Reputation: 2599

If anyone is needing to do this from a JSON string for example

var myJson = [{"Code":"slide_1.png","Description":"slide_1"},{"Code":"slide_2.png","Description":"slide_2"},{"Code":"slide_3.png","Description":"slide_3"}]

You can use var newJsonArray = JSON.Parse(myJson) and you will get Array[3] 0 : Object 1 : Object 2 : Object

At which point you can access it by simply saying newJsonArray[i].Code or whatever property inside the array you want to use. Hope this helps!

Upvotes: 0

Strille
Strille

Reputation: 5781

$.each(data, function (i, item) {
    console.log(item.outlet_name);
});

Or without jQuery:

for (var i=0;i<data.length;i+=1) {
    console.log(data[i].outlet_name);
}

Ok, if you want to iterate over each object you can write:

$.each(data, function (i, item) {
    console.log("Values in object " + i + ":");
    $.each(item, function(key, value) {
        console.log(key + " = " + value);
    });
});

Upvotes: 8

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