CODEWITHSUNDEEP
carraysstringprintf
mrigendra
mrigendra

Reputation: 1556

String size is equal to number of characters

I was making a basic program of strings and did this. There is a string in this way:

#include<stdio.h>
int main()
{
    char str[7]="network";
    printf("%s",str);
    return 0;
}

It prints network.In my view, it should not print network. Some garbage value should be printed because '\0' does not end this character array. So how it got printed? There were no warning or errors too.

Upvotes: 2

Views: 147

Answers (4)

idoby
idoby

Reputation: 927

It's possible that stack pages start off completely zeroed in your system, so the string is actually null-terminated in memory, but not thanks to your code.

Try looking at the program in memory using a debugger, reading your platform documentation or printing out the contents of str[7] to get some clues. Doing so invokes undefined behavior but it's irrelevant when you're trying to figure out what your specific compiler and OS are doing at one given point in time.

Upvotes: 0

Yu Hao
Yu Hao

Reputation: 122383

That's because

char str[7]="network";

is the same as

char str[7]={'n','e','t','w','o','r','k'};

str is a valid char array, but not a string, because it's no null-terminated. So it's undefined behavior to use %s to print it.

Reference: C FAQ: Is char a[3] = "abc"; legal? What does it mean?

Upvotes: 3

Sohil Omer
Sohil Omer

Reputation: 1181

char str[7]="network";

you did not provide enough space for the string 

char str[8]="network";

Upvotes: 0

Gangadhar
Gangadhar

Reputation: 10516

char str[7]="network";

This Invokes Undefined behavior.

You did not declared array with enough space

This should be 

char str[8]="network";

Upvotes: 3

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