Reputation: 687
I have some buttons with same id - previewPhoto. I'm using fancybox to display photo. But all button displays the same image. Where could be a problem, my 'photo' and 'id' vars are different.
$(function() {
$('button#previewPhoto').each(function() {
photo = $(this).val();
id = $(this).attr("title");
link = 'http://domain.com/members/photos/'+id+'/'+photo;
$(this).click(function() {
$.fancybox({
//'orig' : $(this),
'padding' : 0,
'href' : link,
'transitionIn' : 'elastic',
'transitionOut' : 'elastic'
});
});
});
});
Upvotes: 0
Views: 183
Reputation: 41143
You don't need .each()
, simply do this :
jQuery(function ($) {
$(".previewPhoto").on("click", function () {
var photo = $(this).val(),
id = this.title,
link = 'http://farm8.staticflickr.com/' + id + '/' + photo;
$.fancybox(link, {
// API options here
});
});
});
See JSFIDDLE
NOTE: .on()
requires jQuery v.1.7+
Upvotes: 1