CODEWITHSUNDEEP
php
Tadas V.
Tadas V.

Reputation: 835

How to find string consisting of digit and symbol, like "2. "(space after dot) in PHP?

How do you break the string into array starting at its listing number, for example "2. " in the string.

Input:
1. new zealand 0.909991233 2. france and it territories 0.114444444 3. united states 0.99991119991 and so on

Output:

array (
   "1. new zealand 0.909991233",
   "2. france and it territories 0.114444444",
   "3. united states 0.99991119991"
)

Thanks in advance!

PS. I know its not very easy;)

Upvotes: 0

Views: 77

Answers (3)

Passerby
Passerby

Reputation: 10080

Extending from comment:

In case of two or more digits index, you can be a little more aggressive in RegExp:

array_map("trim",preg_split('#(?=\W[0-9]+\.\s+)#',"1. new zealand 0.909991233 22. france and it territories 0.114444444 333. united states 0.99991119991 and so on"))

outputs

Array
(
    [0] => 1. new zealand 0.909991233
    [1] => 22. france and it territories 0.114444444
    [2] => 333. united states 0.99991119991 and so on
)

Live demo

Upvotes: 0

jerjer
jerjer

Reputation: 8766

this should do it:

$str = "1. new zealand 0.909991233 2. france and it territories 0.114444444 3. united states 0.99991119991";

$pattern = '/(\d+\.\s)/i';
$replacement = '; $1';
$str = preg_replace($pattern, $replacement, $str);
$arr = explode('; ', $str);

echo implode("<br>", $arr);

Upvotes: 1

DACrosby
DACrosby

Reputation: 11460

Not too bad, one line really that does the work.

<?php
// Input
$input = "1. new zealand 0.909991233 2. france and it territories 0.114444444 3. united states 0.99991119991";

// Split the input
$ex = preg_split( "#(?=\d+\.\s+)#", $input);

// (Optional) Lose the empty result
unset( $ex[0] );

// Output
var_dump( $ex );

http://codepad.org/wxtmbU15

Upvotes: 0

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