Reputation: 1270
I have two templates index.html and search_results.html in the same directory.
Both have the following code snippet
<link rel="stylesheet" type="text/css" href="{{ STATIC_URL }}bootstrap/css/bootstrap.min.css" media="screen" />
The css file loads on the index template:
"GET /static/bootstrap/css/bootstrap.min.css HTTP/1.1" 304 0
However, does not for the search_results template:
"GET /search/static/bootstrap/css/bootstrap.min.css HTTP/1.1" 404 2133
Since it includes the /search.
I'm wondering how to omit the /search/ portion in trying to load the css file in my second template, since that template all have urls starting with /search/.
my urls.py:
urlpatterns = patterns('',
url(r'^$', 'home.views.index'),
url(r'^search/$', 'home.views.film_chart_view')
)
Upvotes: 0
Views: 511
Reputation: 1670
Clearly, you are missing the slash /
at the beginning of the static URL.
The dirty fix: Change the line in your template to
<link rel="stylesheet" type="text/css" href="/{{ STATIC_URL }}bootstrap/css/bootstrap.min.css" media="screen" />
The clean fix:
Add a slash at the beginning of the STATIC_URL
variable in your settings file. It must probably look like this:
STATIC_URL = '/static/'
Upvotes: 2