Reputation: 1060
I know this is a very basic question but I'm new to XML and while it seems simple, I can't find a simple answer anywhere. I have an XML document that looks like this:
<?xml version="1.0" encoding="UTF-8"?>
<root version="1">
<targets>
<target type="email">
<property name="to">[email protected]</property>
</target>
<target type="fob"/>
</targets>
<observation uniqueID="00A60D" deviceID="308610ea23">
<field name="field1">test1</field>
<field name="field2">test2</field>
</observation>
and I'm trying to either select a subset of that xml, or remove nodes, to get it pared down to:
<observation uniqueID="00A60D" deviceID="308610ea23">
<field name="attachments">
<string>1910.jpg</string>
</field>
<field name="field1">test1</field>
<field name="field2">test2</field>
</observation>
So that I can deserialize it into an object. Any help is greatly appreciated.
Upvotes: 0
Views: 1695
Reputation: 934
Here is a XML to LINQ Version:
dynamic root= XElement.Load(dataStream).Descendants("root")
.Select(element => element.Value).ToArray();
This will give all the root
element from the document.And you can access root
Upvotes: 1
Reputation: 8394
XElement root = XElement.Parse("<root version ..." // etc. to parse a string.
// Use XElement.Load to load a file.
var observations = root.Elements("observation");
It assumes one root (by definition) and possibly multiple observation
elements.
Upvotes: 0
Reputation: 15951
You can use XPath:
string xml = "<?xml version=\"1.0\" encoding=\"UTF-8\"?>" +
"<root version=\"1\">" +
"<targets>" +
"<target type=\"email\">" +
"<property name=\"to\">[email protected]</property>" +
"</target>" +
"<target type=\"fob\"/>" +
"</targets>" +
"<observation uniqueID=\"00A60D\" deviceID=\"308610ea23\">" +
"<field name=\"field1\">test1</field>" +
"<field name=\"field2\">test2</field>" +
"</observation>" +
"</root>";
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
XmlElement root = doc.DocumentElement;
var observationNode = root.SelectSingleNode("/root/observation");
var observationXml = observationNode.OuterXml;
Upvotes: 1