CODEWITHSUNDEEP
phphtml
RKh
RKh

Reputation: 14161

Open page with Form pre-filled

I have an entry Form. When the page is loaded, it must check:

if ($_SESSION[WorkMode] == 'UPDATE')

Then fill the Form with values from the database, else open a blank Form.

If I fetch the results in a different PHP file and call this .php file on load, how to fill the Form.

Upvotes: 0

Views: 12003

Answers (3)

Wilfred Derksen
Wilfred Derksen

Reputation: 1

I found out that the following did it for me, adding the variable after a column.

<label>Firstname &nbsp;&nbsp;&nbsp;: </label><input type="text" name="Firstname" value= "<?php echo (isset($_POST['firstname'])) ? htmlspecialchars($_POST['firstname']) : $firstname;?>"

Upvotes: 0

halfdan
halfdan

Reputation: 34214

Set the variables that hold the values for your form, then include the "template" of the form you're having.

File 1:

<?php
$res = mysql_query("..");
if($res) {
  $row = mysql_fetch_assoc($res);
  $name = $row['name'];
  $birthday = $row['birthday'];
  ...
  include('form.tpl');
}

File 2 (form.tpl)

<form action="">
  <input type="text" name="username" value="<?php isset($name)?$name:""; ?>" />
  .. and so on
</form>

Alternatetively you can use a full blown template engine like Smarty to do the job for you.

Best wishes,
Fabian

Upvotes: 5

antpaw
antpaw

Reputation: 15985

$formvalue = NULL;
if ($_SESSION[WorkMode] == 'UPDATE')
    $formvalue = $some_database_value;
echo '<input type="text" name="myname" value="'.$formvalue .'" />';

Upvotes: 0

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