Reputation: 125
How to convert string value into integer and multiply the converted value to integer so that I can get the result as 300.00. See example below -
int value = 5;
String str = "60.00 Cur";
If I code like these then I am getting error -
Float f = new Float(app.price.get(position));
double d = f.doubleValue();
int i = (int)d;
Upvotes: 0
Views: 541
Reputation: 5554
Can you try the following code and see if this is what you want? The final answer will be present in the variable "result".
String str = "60.00 USD";
int value = 5;
String dollarValue = str.split(" ")[0];
Float price = Float.parseFloat(dollarValue );
Float result = price * value;
DecimalFormat df = new DecimalFormat("#.##");
df.setMinimumFractionDigits(2);
String resultString = df.format(result);
You will get a "NumberFormatException" if you try to parseFloat
on str directly as it contains the string USD. Here we will split that and take the first part.
Edit: Try the newly added code with DecimalFormat
and use the resultString for your purpose.
Upvotes: 0
Reputation: 2000
Use,
Integer.parseInt("value you want to parse as int")
likewise you can use,
Double.parseDouble("value");
This is answer for your Question
int result = Integer.parseInt("150.00 USD")* Integer.parseInt("5");
Upvotes: 0
Reputation: 54672
you will get a NumberFormatException
as "60.00 USD"
is not a float. To make it right you have to remove the currency. There can be many ways to remove the usd. For example
String s = "60.00 USD";
s = s.replace(" USD" , "");
or if the currency is not fixed
s = s.split(" ")[0];
Now you have A string s whose value is "60.00"
so you can do this now
float f = Float.parseFloat(s);
Upvotes: 0
Reputation: 248
If the String only contains numeric values you can use
Integer.parseInt(string); or Float.parseFloat(string);
As for your example, the "USD" part will cause this to fail, so you'll probbaly have to strip this part out first.
e.g. string.split(" ");
Upvotes: 0
Reputation: 4030
Use Interger.parseInt(String) or Float.parseFloat(String)
refer API documentation
http://docs.oracle.com/javase/6/docs/api/java/lang/Integer.html
Upvotes: 2
Reputation: 135992
try this
int n = NumberFormat.getIntegerInstance().parse(str).intValue();
Upvotes: 1