CODEWITHSUNDEEP
haskell
Alex
Alex

Reputation: 667

basic haskell : Converting Type to Int

If I have a type, eg insurance number which is a int.

Is there anyway I can convert insurancenumber to int for use in a comparing function?

intNI :: NI -> Int
intNI x = Int (x)

Upvotes: 0

Views: 908

Answers (1)

kqr
kqr

Reputation: 15028

If, as I suspect, NI is defined as

type NI = Int

then you can just say

intNI :: NI -> Int
intNI x = fromIntegral x

or, after eta-conversion:

intNI :: NI -> Int
intNI = fromIntegral

On the other hand, it seems that

data NI = NI Int

in which case the right way to go is pattern matching, like so:

intNI (NI x) = x

This will extract the x bit out of NI x and return it.

Upvotes: 1

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