Reputation: 1
I need to eventually display all the items in my list that have the file ending .shp. So I need to be able to index each list item separately. Any suggestions?
This is what I have so far:
folderPath = r'K:\geog 173\LabData'
import os
import arcpy
arcpy.env.workspace = (folderPath)
arcpy.env.overwriteOutput = True
fileList = os.listdir(folderPath)
print fileList
"""Section 2: Identify and Print the number
and names of all shapefiles in the file list:"""
numberShp = 0
shpList= list()
for fileName in fileList:
print fileName
fileType = fileName[-4:]
print fileType
if fileType == '.shp':
numberShp +=1
shpList.append(fileName)
print shpList
print numberShp
Upvotes: 0
Views: 95
Reputation: 1338
Can You Please specify the desired output format. That would make the job easy...
One Probable Answer would be
fileList = [f for f in os.listdir('K:\geog 173\LabData') if f.endswith('.shp')]
for i,val in enumerate(fileList):
print '%d. %s' %(i,val)
#If u want to print the length of the list again...
print len(fileList)
Upvotes: 0
Reputation: 23575
You could do this quite easily with list comprehensions and str.endswith()
:
shpList = [fileName for fileName in fileList if fileName.endswith('.shp')]
print shpList
print len(shpList)
Upvotes: 1