CODEWITHSUNDEEP
java
TheGreatDragon
TheGreatDragon

Reputation: 3

how to convert a string to an int in java and and separate the values of the string?

I am working on a board style game in java. currently the board is initialized in a 2d array. A player can make a move by enter the color of his chip plus his move so for example by entering: "W c 3" W = the color of the chip/player c is the letter corresponding to the column and 6 is the row. I need to be able to get the values from the string and update the board's row and column. So " a 1" should be row =1 col = 1. "b 1" should be row = 1 col = 2 "e 5" would be row = 5 col = 5 as an example.

How would I go about doing something like that?

here is my code in my move.java class if this helps: The method i'm working on is the Move (String str) method. 

public class Move implements Comparable<Move>{
    static final int PASS_VALUE = 0; 
    int row, col; 
    boolean movement;
    int pass;
    int pos;
    Board board; 
    /**
     * 
     * Default constructor that initializes a pass move
     */
    Move(){
        row = PASS_VALUE; 
        col = PASS_VALUE;
    }//Move default contructor
   /**
    * 
    * @param rowValue
    * @param colValue 
    */
    Move(int rowValue, int colValue){
        row = rowValue; 
        col = colValue; 
    }//Move constructor

    /**
     * 
     * @param oldMove -- Move to be copied 
     */
    Move(Move oldMove){
        row = oldMove.row;
        col = oldMove.col; 

    }//Move clone constructor

    Move(String str) {
        //int i = Integer.parseInt( str );


    } //Move String constructor

    Move (int positions) {

    }//Move Positions constructor

    /**
     * 
     * @return string value of Move 
     */
    @Override
    public String toString(){
        String result ="";
        String headers = " abcdefgh";
        char colLetter = headers.charAt(col);
        result = colLetter + " " + row; 

        return result;
    }//toString
    /**
     * 
     * @param otherMove -- move to be compared 
     * @return 
     *      -1 if this move precedes otherMove
     *       0 if this move equals otherMove
     *       1 if this move succeeds otherMove
     */
    @Override
    public int compareTo(Move otherMove){
        return 0;
    }//compareTo

   boolean isAMove() {
        return movement; 
    }
   boolean isAPass(){
       return row == PASS_VALUE;
   }
}//Move

***Keep in mind that the string variable (str) is being populated by this code: 

Move getOpponentMove(BufferedReader keyboard) throws IOException {
        OthelloOut.printComment("Please enter your move");
        InputStreamReader reader = new InputStreamReader(System.in);
        BufferedReader in = new BufferedReader(reader);
        String initializeStr = keyboard.readLine();
        Move opponentMove = new Move(initializeStr);

        return opponentMove;
    }

Upvotes: 0

Views: 999

Answers (4)

burmat
burmat

Reputation: 2548

You can do it this way (comments explain it):

// create an array of the alphabet from a - z
public String[] alpha = {"a", "b", "c", "d", "e"}; //...etc.

// here is your value
String input = "e 5";

// split it at the space
String[] split = input.split(" ");

// find it in the array and add 1 to get your row (because arrays start at 0)
int row = Arrays.asList(alpha).indexOf(split[0]) + 1;

// get the column as well
int column = Integer.parseInt(split[1]);

Upvotes: 0

fvdalcin
fvdalcin

Reputation: 1047

Do it in the following order:

Assuming you have an input of the form:

String input = new String("W c 3");

1.Parse the input with split():

String color = input.split(" ")[0];
String column = input.split(" ")[1];

2.For the int variable, call the method parseInt()

int row = Integer.parseInt(input.split(" ")[2]);

Upvotes: 0

Bathsheba
Bathsheba

Reputation: 234875

If your string is strictly of the form "a b" where a is in the range a a - z, and b is a number in the range 0 - 9 then do something like

/* s is your string */
int row = s.charAt(0) - 'a' + 1;
int col = s.charAt(2) - '0' + 1;

where I've exploited the ASCII character number values and the fact that 'a' is a byte data type.

Of course, in production, you ought to pre-validate s (check its length, whether or not the second character is a space etc. You could even use a regular expression check via Java's String.matches method). All you'd have to do is check if

s.matches("[a-z] [0-9]")

is true. My method is a throwback to the good old C days.

Upvotes: 1

Jeremy D
Jeremy D

Reputation: 4855

I would do this:

  • split using space as delimiter
  • indexOf(letter) in "abcdefg....xyz"
  • Integer.parseInt(digit)

Upvotes: 0

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