Reputation: 131
I,m a total PHP newbie, I learned about arrays yesterday and my boss asked me to write a PHP form, I found one on W3 schools and ended up with
<html>
<body>
<form action="upload_file.php" method="post" enctype="multipart/form-data">
<label for="file">Filename:</label>
<input type="file" name="file" id="file"><br>
<input type="submit" name="submit" value="Submit">
</form>
</body>
</html>
<?php
$allowedEXTs = array("jpeg", "jpg", "png");
$temp = explode(".", $_FILES["file"]["name"]);
$extension = end ($temp);
if ((($_FILES["file"] ["type"] == "image/jpeg")
|| ($_FILES ["file"] ["type"] == "image/jpg")
|| ($_FILES ["file"] ["type"] == "image/png"))
&& ($_FILES ["file"] ["size"] < 10240)
&& in_array($extension, $allowedExts))
{
if ($_FILES["file"] ["error"] > 0)
{
echo "Error: " . $_Files["file"] ["error"] . "<br>";
}
else
{
echo "Upload: " . $_FILES ["file"] ["name"] . "<br>";
echo "Type: " . $_FILES ["file"] ["name"] . "<br>";
echo "Size: " . $_FILES ["file"] ["size"] / 10240 . " kB<br>";
echo "Stored in:" . $_FILES ["file"] ["tmp_name"];
}
if (file_exists("upload/" . $_FILES["file"]["name"]))
{
echo $_FILES ["file"] ["name"] . "already exists.";
}
else
{
move_uploaded_files ($_FILES ["file"]["tmp_name"], "upload/" . $_FILES ["file"] ["name"]);
}
}
else
{
echo "Invalid file";
}
?>
I basically don't know why this is throwing up "Warning: in_array() expects parameter 2 to be array, null given in" that error, can anyone lend a helping hand?
Upvotes: 1
Views: 346
Reputation: 635
$allowedEXTs = array("jpeg", "jpg", "png");
Declared like this,
&& in_array($extension, $allowedExts))
Called like this,
You have declared it with "EXTs" and calling it as "Exts"... Hence the error.
Upvotes: 3
Reputation: 1525
You declare the array with $allowedEXTs, but it is spelled small in the if statement.
Upvotes: 0
Reputation: 4765
You define the array with
$allowedEXTs = array("jpeg", "jpg", "png");
then call it with
&& in_array($extension, $allowedExts))
Make sure the case is the same every time you call a variable.
Same with this line which should be $_FILES
:
echo "Error: " . $_Files["file"] ["error"] . "<br>";
Upvotes: 1