Reputation: 5603
I have an array that I am looping through and pushing specific values to a separate array. EX:
first_array = ["Promoter: 8", "Passive: 7"]
I want to push every value that is an integer to a separate array, that would look like this in the end:
final_array = [8,7]
It would be nice for the values in the new array to be integers. I can't think of a way to push all numeric values within a string to a new array, but what would be the best option to do what I am wanting?
Upvotes: 1
Views: 124
Reputation: 110755
If the integer part of each string in (which look like members of a hash) is always preceded by at least one space, and there is no other whitespace (other than possibly at the beginning of the string), you could do this:
first_array = ["Promoter: 8", "Passive: 7"]
Hash[*first_array.map(&:split).flatten].values.map(&:to_i) # => [8,7]
Note the need for the splat:
Hash[*["Promoter:", "8", "Passive:", "7"]]
=> Hash["Promoter:", "8", "Passive:", "7"]
=> {"Promoter:" => "8", "Passive:" => "7"}
Upvotes: 0
Reputation: 12588
Your question, as formulated, has an easy practical answer, already provided by others. But it seems to me, that your array of strings
a = ["Promoter: 8", "Passive: 7"]
envies being a Hash
. So, from broader perspective, I would take freedom of converting it to a Hash first:
require 'pyper' # (type "gem install pyper" in your command line to install it)
hsh = Hash[ a.τBmm2dτ &/(\w+): *(\d+)/.method( :match ) ]
#=> {"Promoter"=>"8", "Passive"=>"7"}
# (The construction of #τBmm2dτ Pyper method will be explained in the appendix.)
Now, having your input data in a hash, you can do things with them more easily, eg.
hsh.τmbtiτ
#=> [8, 7]
APPENDIX: Explanation of the Pyper methods.
Pyper methods are similar to Lisp #car/#cdr methods in that, that a combination of
letters controls the method behavior. In the first method, #τBmm2dτ
:
So, in #τBmm2dτ
, Bm
applies the block as follows:
x = ["Promoter: 8", "Passive: 7"].map &/(\w+): *(\d+)/.method( :match )
#=> [#<MatchData "Promoter: 8" 1:"Promoter" 2:"8">, #<MatchData "Passive: 7" 1:"Passive" 2:"7">]
# Which results in an array of 2 MatchData objects.
Then, m2d
chars map (m
) the MatchData objects using 2
and d
chars. Character 2
gives
x = x.map { |e| e.to_a.take 3 }
#=> [["Promoter: 8", "Promoter", "8"], ["Passive: 7", "Passive", "7"]]
and d
removes the first element from each:
x = x.map { |e| e.drop 1 }
#=> [["Promoter", "8"], ["Passive", "7"]]
In the secon method, #τmbtiτ
, m
means again #map
, b
means take the second element, and ti
means convert it to Integer
:
{"Promoter"=>"8", "Passive"=>"7"}.to_a.map { |e| Integer e[1] }
#=> [8, 7]
Upvotes: 1
Reputation: 13921
And I have to add this super short but complicated one-liner solution:
a = ["Promoter: 8", "Passive: 7"]
p a.grep(/(\d+)/){$&.to_i} #=> [8,7]
Upvotes: 1
Reputation: 7334
first_array.map{|a| a.match(/\d+/)}.compact.map{|a| a[0].to_i }
Upvotes: 1