CODEWITHSUNDEEP
phpjqueryimageloops
Matt Maclennan
Matt Maclennan

Reputation: 1304

Change img to background image in PHP loop jQuery

I'm trying to convert loaded imgtags to background images using jQuery, however, the images are being loaded in a PHP while loop. When I try implementing the jQuery, only the last img tag is looked at by the jQuery. Here is my code

PHP

$query = mysqli_query($dbleads, "SELECT * FROM plugin_blog WHERE published = 1 ORDER BY date_added DESC LIMIT 0,20");
$i = 0;
$j=-1;
while ($row=mysqli_fetch_array($query)){
    preg_match('/(<img[^>]+>)/i', $row['html'], $matches);
    $img = $matches[1];
    ++$i;
    if ($i%2 == 0){
        ++$j;
        echo "<div class='masonryImage tweets' style='width:300px; height:175px;'><div class='tweet-content'>" . $tweets[$j] . "</div></div>";
    }
    else{
        echo "<div class='masonryImage blogImage' style='width: 300px; height:200px;'>" . $img . " </div>";
    }
}

jQuery

$j('div.blogImage img').each(function() { 
   var imageSrc = $j(this).attr('src');

   $j(this).remove();
   $j('.blogImage').html('<div class="backbg"></div>');
   $j('.backbg').css('background-image', 'url(' + imageSrc + ')');
   $j('.backbg').css('background-repeat','no-repeat');
   $j('.backbg').css('background-position','center');
   $j('.backbg').css('background-size','cover');
   $j('.backbg').css('width','100%');
   $j('.backbg').css('height','100%');
});

Any ideas?

Upvotes: 0

Views: 675

Answers (1)

dave
dave

Reputation: 64657

You are setting every .backbg's css on the last iteration.
When you run $j('.backbg').css('background-image', 'url(' + imageSrc + ')'); the last time, you are saying "find EVERY .backbg, even the ones I've already done, and set their css".

You need to do something like:

var imageSrc = $j(this).attr('src');
var blogImg = $j(this).parent();
$j(this).remove();
blogImg.html('<div class="backbg"></div>');
blogImg.find('.backbg').css('background-image', 'url(' + imageSrc + ')');

Upvotes: 1

Related Questions