CODEWITHSUNDEEP
c++cparsing
Raghav Guar
Raghav Guar

Reputation: 61

String parsing based on escape character

I am trying to parse the following string:

"USBSTOR\DISK&VEN_JETFLASH&PROD_TRANSCEND_8GB&REV_1100\00H8096XQ9UW1BQ5&0:JetFlash Transcend 8GB USB Device"

based on '\' (character)

Prob 1: but this character is considered as escape character

Prob 2: \0 in the mid of the string is considered as the end of the string.

I tried so many ways.

(i) I tried to replace '\' with another character like '$' and tried to parse with sscanf() but it did not work.

Can you people suggest something?

#include <string.h>
#include <stdio.h>

int main()
{
    char str[80] = "This is \www.tutorialspoint.com \website";
    const char s[2] = "\\";
    char *token;

    /* get the first token */
    token = strtok(str, s);

    /* walk through other tokens */
    while( token != NULL )
    {
      printf( " %s\n", token );

      token = strtok(NULL, s);
    }

    return(0);
}

Upvotes: 0

Views: 1321

Answers (2)

0xF1
0xF1

Reputation: 6116

Remember Escape Sequences (\\, \n, \0, etc.)are a single character.

To have \ character in a string which is initialized in the code itself, it is mandatory to use \\ in the initialization string.

If you are providing input at runtime, then you should use \ (Single BackSlash) for input, Providing input this way will not consider \0 as ASCII-0 character, instead it will be treated as \ followed by 0 (two characters).

In your case, you want to parse "USBSTOR\D...", you can do it in either by storing it in a const string (Remember \\ in this case) or by providing it as input form console or a disk file (Here you should use single \).

In any of the above ways, when you read the string, you will get the correct character expected, example, for first case \\ will resolve to \ when you read it or print it.

Upvotes: 1

Raja
Raja

Reputation: 3106

Make this modification char str[80] = "This is \\www.tutorialspoint.com \\website";

With that, your output is:

This is 
www.tutorialspoint.com 
website

Remember: Any string literal that you use in code requires the escape sequence for backslash.

Upvotes: 1

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