Reputation: 1
here is my for loop... jGRASP says there is a problem beginning in the line with my for loop, I can't see the problem and would like some help to fix my code...
public class DirectoryLookup { public static void main(String[] args) throws IOException {
if (args.length == 0) {
System.out.println("Please supply data file");
System.exit(0);
}
else {
System.out.println("Database server is Ready for Number Lookups!");
}
File inputDataFile = new File(args[0]);
Scanner inputFile = new Scanner(inputDataFile)
Scanner input = new Scanner(input.in);
int n = inputFile.nextInt();
int list[] = new int[n];
found = false;
while (Scanner.hasNext()); {
System.out.println("Enter number to check value");
int x = input.nextInt();
for (i = 0, i < n, i++);
if (x == list(i)); {
found = true; break
System.out.println("x is in the list");
else {
System.out.println("x is not in the list");
}
}
Upvotes: 0
Views: 583
Reputation: 69
The first problem that I see in your for loop is that you never declare i as an integer. You would have to say for(int i = 0... ).
The second problem that I see is that you are forgetting your brackets for the for loop. It is ending in a semi colon and not a bracket and closing bracket.
The third problem that I see is that you never close your if statement brackets. right now the else statement is in the if statement. which does not make any logical or syntactical sense.
Your while statement conditions are wrong also. Instead of scanner.blah you need to use the variable name used input or inputfile.
You never declared your boolean variable found.
Hope that helped,
Best regards
Upvotes: 0
Reputation: 178313
You have semicolons following your while
condition, your for
loop declaration, and your if
condition. They need to be removed, otherwise Java will treat the semicolon itself as the body.
The semicolon is missing on your break
statement, and the ending brace }
is missing before your else
.
Upvotes: 5