CODEWITHSUNDEEP
pythonlistloopsfor-looppretty-print
chin2
chin2

Reputation: 21

Loop print of 2 columns in to 1

Suppose I have an array of 2 columns. It looks like this column1 = [1,2,3,...,830] column2 = [a,b,c,...]

I want to have output in a print form of single columns, that includes value of both columns one by one. output form: column = [1,a,2,b ....]

I tried to do by this code,

dat0 = np.genfromtxt("\", delimiter = ',')
mu = dat0[:,0]
A = dat0[:,1]
print(mu,A)
R = np.arange(0,829,1)
l = len(mu)
K = np.zeros((l, 1))
txtfile = open("output_all.txt",'w')
for x in mu:
    i = 0
    K[i,0] = x
    dat0[i,1] = M
    txtfile.write(str(x))
    txtfile.write('\n')
    txtfile.write(str(M))
    txtfile.write('\n')
print K

Upvotes: 0

Views: 154

Answers (2)

Niek de Klein
Niek de Klein

Reputation: 8824

I'm sure there is a better way to do this, but one method is

>>> a = numpy.array([[1,2,3], ['a','b','c'],['d','e','f']]) 
>>> new_a = []
>>> for column in range(0,a.shape[1]):           # a.shape[1] is the number of columns in a
...     for row in range(0,a.shape[1]):          # a.shape[0] is the number of rows in a
...             new_a.append(a[row][column])   
...
>>> numpy.array(new_a) 
array(['1', 'a', 'd', '2', 'b', 'e', '3', 'c', 'f'],
     dtype='|S1')

Upvotes: 0

user27030
user27030

Reputation:

I do not understand your code completely, is the reference to numpy really relevant for your question? What is M?

If you have two lists of the same lengths you can get pairs of elements using the zip builtin.

A = [1, 2, 3]
B = ['a', 'b', 'c']

for a, b in zip(A, B):
    print(a)
    print(b)

This will print

1
a
2
b
3
c

Upvotes: 1

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