Reputation: 845
Supose I have this XML:
<Items>
<Car name="12">Mercedes</Car>
<Bike name="23">Gt</Bike>
<House name="gt">123</House>
<Skate name="as">111</Skate>
<Plane name="bb">5522</Plane>
<tv name="sss">Sony</tv>
</Items>
And the following XSLT:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>
<xsl:template match="Items">
<table>
<xsl:for-each select="*[position() mod 2 != 0]">
<tr>
<td>
<xsl:value-of select="name()"/>
</td>
<td>
<xsl:value-of select="."/>
</td>
<td>
<xsl:value-of select="name(following-sibling::*)"/>
</td>
<td>
<xsl:value-of select="following-sibling::*"/>
</td>
</tr>
</xsl:for-each>
</table>
</xsl:template>
</xsl:stylesheet>
The output Im getting is:
<table>
<tr>
<td>Car</td>
<td>Mercedes</td>
<td>Bike</td>
<td>Gt</td>
</tr>
<tr>
<td>House</td>
<td>123</td>
<td>Skate</td>
<td>111</td>
</tr>
<tr>
<td>Plane</td>
<td>5522</td>
<td>tv</td>
<td>Sony</td>
</tr>
</table>
But what I need is the attribute @name
instead of the node name... how can I do that??
What I need is this:
<table>
<tr>
<td>12</td>
<td>Mercedes</td>
<td>23</td>
<td>Gt</td>
</tr>
<tr>
<td>gt</td>
<td>123</td>
<td>as</td>
<td>111</td>
</tr>
<tr>
<td>bb</td>
<td>5522</td>
<td>ss</td>
<td>sony</td>
</tr>
</table>
I know that in the first <td>
I can use @name
, but how can I get the attribute "name" of the following sibling node in the other <td>
?
Upvotes: 1
Views: 11564
Reputation: 11961
<xsl:value-of select="following-sibling::*/@name"/>
This should return the name attribute of the following sibling.
Edit
It appears
<xsl:value-of select="following-sibling::*[1]/@name"/>
Is the correct way to do it.
Upvotes: 4