CODEWITHSUNDEEP
javascriptjqueryunit-testing
BeraCim
BeraCim

Reputation: 2347

Is there anyway to unit test javascript functions defined within a function?

I would just like to ask whether I would be able to unit test the code inside ExternalFunction within the document.ready? I have tried many things for a while now and still couldn't work out how, and am at my wits end.

$(document).ready(function () {
    var originalExternalFunction = ExternalFunction;
    ExternalFunction = function(context, param) {
        // trying to unit test the stuff in here!
    }
}

I'm unit testing using JsTestDriver. Test declaration is something like TestThisTest.prototype.test_this - function() {};

Thanks in advance.

Upvotes: 3

Views: 325

Answers (4)

gnarf
gnarf

Reputation: 106412

You could use a closure to generate your callback function:

// create function to make your "extension" function
function createHookFunction(callback) {
  // return a function 
  return function(context, param) {
     var ret;
     // // trying to unit test the stuff in here!


     if (typeof callback == 'function') {
       // if you want to trap the return value from callback, 
       // ret = callback.apply(...);
       callback.apply(this, arguments);
     }
     return ret;
  };
}

// your hook now becomes:
$(document).ready(function() {
  ExternalFunction = createHookFunction(ExternalFunction);
});

// and your unit test becomes:
var funcToTest = createHookFunction();
funcToTest(testContext, testParam);

// And, you could even test that the callback itself gets called

function someTest() {
  var testContext = {}, testParam='test';
  var callbackCalled = false;
  var funcToTest = createHookFunction(function(context, param) {
    callbackCalled = (context === testContext) && (param === testParam);
  });
  return (funcToTest(testContext, testParam) == 'Expected Return') && callbackCalled;
}

Upvotes: 0

Paul Butcher
Paul Butcher

Reputation: 6956

Since, in your example, ExternalFunction is not declared within the scope of the function, it is global (or at least, in whatever scope it may have been defined in outside ready). You can therefore test it by calling it as a global.

The trouble is, in order to assign the function to ExternalFunction, you have to run ready (which you could run manually, if you need). This means that if you put any other functionality in ready, then no, it is not unit testable. If your example code is an accurate reflection of reality, then I suppose it is kinda testable.

The point of a construct like this, is to hide the inner function. If you don't wish to hide it, then Anon.'s suggestion of defining newExternalFunction in a more accessible scope is what you need.

If your function needs to be a closure using variables from within ready, you could define newExternalFunction thus:

   var newExternalFunction;
    $(document).ready(function () {
        var originalExternalFunction = ExternalFunction;
        newExternalFunction = function(context, param) {
            // trying to unit test the stuff in here!
        }
        ExternalFunction = newExternalFunction;
    }

You would still need to ensure that ready has run, prior to unit testing, but you wouldn't have to rely on ExternalFunction not being reset to originalExternalFunction.

Upvotes: 2

FryGuy
FryGuy

Reputation: 8744

Theoretically, you could do something like:

ExternalFunction = function() { }
ExecuteDocumentReady(); // implement a mock on $(document).ready(fn) to store the function, and then execute it here

ExternalFunction(fakeContext, fakeParam);
assert(fakeContext.foo == 12); // or whatever you need it to do

That being said, I'm not sure exactly how to do that in javascript.

Upvotes: 0

Anon.
Anon.

Reputation: 60043

You could do something like:

function newExternalFunction(context, param) {
    //etc.
}

$(document).ready(function () {
    var originalExternalFunction = ExternalFunction;
    ExternalFunction = newExternalFunction;
}

Then it's relatively straightforward to run your unit tests on newExternalFunction.

Upvotes: 1

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