CODEWITHSUNDEEP
phpimagefileurldirectory
Rudi tabuti
Rudi tabuti

Reputation: 23

How to call image url from directory using php

I want to display the image and the image url of a directory
I found this code, but there is a dot before the filename. 

<?php
$files = glob("./images/*.*");
for ($i=0; $i<count($files); $i++) {
    $image = $files[$i];
    print "<textarea>";
    print "http://" .$_SERVER['SERVER_NAME'].$image;
    print "</textarea>"."<br />";
    echo '<img src="'.$image .'" />'."<br /><br />";    
}
?>

the result will be like this :

<textarea>http://domain.com./images/filename.png<textarea>
<img src="./images/filename.png" />

please help to fix this. thanks.

Upvotes: 0

Views: 3286

Answers (1)

Rudi tabuti
Rudi tabuti

Reputation: 23

I solved the problem by using the following:

<?php
$files = glob("images/*.*");
for ($i=0; $i<count($files); $i++) {
    $image = $files[$i];
    echo '<img src="'.$image .'" />'."<br /><br />";   
    print "<textarea>";
    print "http://" .$_SERVER['SERVER_NAME'].$image;
    print "</textarea>"."<br /><br /><br />"; 
}
?>

Upvotes: 2

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