CODEWITHSUNDEEP
javaoverload-resolution
One Two Three
One Two Three

Reputation: 23517

Why is Java picking this overload over the other

Could anyone explain to me why Java is picking the second overload instead of the first?

public static void foo (int a, double b, double...c) {}
public static void foo (double...a) {}
public static void bar ()
{
    // this is the second
    foo(1);
}

I thought when I pass 1 as the argument, Java would have picked the first argument because int is more specific than double?

Thanks

Upvotes: 0

Views: 45

Answers (1)

rgettman
rgettman

Reputation: 178293

The second method is the only one that can match. You have only 1 argument. The first foo has at least two required: an int and a double, so that can't match.

The second foo matches because any number of numbers can match. Java will implicitly promote your int 1 to a double so it can match, with method invocation conversion.

Upvotes: 5

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