XK8ER
XK8ER

Reputation: 780

Alternative to using InStr

how can I use a different function "InStr" this is the code that I am using and works fine but moving away from InStr is my goal

i = InStr(1, Hostname, Environment.Newline)

Upvotes: 10

Views: 51280

Answers (2)

String.Indexof() with several overloads:

Dim jstr = "How much wood could a woodchuck chuck if a woodchuck..."

' Find a character from a starting point
ndx = jstr.IndexOf("w"c)             ' == 2 (first w)
'  or within a range:
ndx = jstr.IndexOf("o"c, 12)         ' == 15 first o past 12 (cOuld)  

'Find a string
ndx = jstr.IndexOf("wood")           ' == 9
' ...from a starting point
ndx = jstr.IndexOf("wood", 10)       ' == 22 (WOODchuck)
' ...or in part of the string
ndx = jstr.IndexOf("chuck", 9, 15)   ' -1 (none in that range)

' using a specified comparison method:
ndx = jstr.IndexOf("WOOD", StringComparison.InvariantCultureIgnoreCase)  ' 9
ndx = jstr.IndexOf("WOOD", nFirst, StringComparison) 
ndx = jstr.IndexOf("WOOD", nFirst, nLast, StringComparison)

There is also a String,LastIndexOf() method to get the last occurance of something in a string also with a variety of overloads.

Available in MSDN or Object Browser (VIEW menu | Object Browser) in the VS near you.

i = Hostname.Indexof(Environment.Newline, 1)

Upvotes: 21

Alezis
Alezis

Reputation: 2759

If you need equivalent C# code you can use Strings class from Microsoft.VisualBasic assembly, thus code can be like following:

using Microsoft.VisualBasic;
. . . 
i = Strings.InStr(1, Hostname, Environment.NewLine);

enter image description here

Another approach is using appropriate String.Indexof function.

Links:

Upvotes: 8

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