CODEWITHSUNDEEP
javascriptjqueryurlsubstring
Aaron Pitts
Aaron Pitts

Reputation: 5

How to get parameters in an url after last occurrence of a certain character

Currently I have some jquery which is getting some parameters from the URL by getting all required parameters after a '#' in the URL. My URL has more than one # therefore I would like it to only select the parameters from after the last # in the URL. So far I have the below (which selects all occurrences of the #). Any ideas on how I can achieve what I want?

params = url.substring(url.indexOf('#') + 1, url.length);

Many thanks

Upvotes: 0

Views: 1095

Answers (2)

iJade
iJade

Reputation: 23791

since you want params after last #

try this

params = url.split('#');
alert(params[params.length-1]);

Upvotes: 0

Harry
Harry

Reputation: 89750

I think you need lastIndexOf() method.

params = url.substring(url.lastIndexOf('#') + 1, url.length);

Upvotes: 3

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