CODEWITHSUNDEEP
androidandroid-intent
user1390816
user1390816

Reputation: 623

Communicate from Service to Activity

I start a service in my Activity following way. After the Service started I close the Activity. If I start the Activity again, I want to receive some informations from the service. How can I do that?

// Activity

@Override
public void onCreate(Bundle savedInstanceState) 
{
   // here I want to receive data from Service
}

Intent i=new Intent(this, AppService.class);

i.putExtra(AppService.TIME, spinner_time.getSelectedItemPosition());

startService(i);


// Service

public class AppService extends Service {

  public static final String TIME="TIME";

  int time_loud;

  Notification note;
  Intent i;

  private boolean flag_silencemode = false;


  @Override
  public int onStartCommand(Intent intent, int flags, int startId) {


    time_loud = intent.getIntExtra(TIME, 0);

    play(time_loud); 

    return(START_NOT_STICKY);
  }

Upvotes: 0

Views: 137

Answers (2)

David
David

Reputation: 7105

I would suggest using the Otto library from Square.

Otto is an event bus designed to decouple different parts of your application while still allowing them to communicate efficiently.

The simple way would be that you create a Bus:

Bus bus = new Bus();

Then you would simply publish an event:

bus.post(new AnswerAvailableEvent(42));

to which your Service is subscribed

@Subscribe public void answerAvailable(AnswerAvailableEvent event) {
    // TODO: React to the event somehow!
}

and then the service would provide a result

@Produce public AnswerAvailableEvent produceAnswer() {
    // Assuming 'lastAnswer' exists.
    return new AnswerAvailableEvent(this.lastAnswer);
}

Upvotes: 2

CommonsWare
CommonsWare

Reputation: 1006744

The simplest solution nowadays, IMHO, is to use a third-party event bus, like Square's Otto (using a @Producer to allow the activity to get the last-sent event of a given type) or greenrobot's EventBus (using a sticky event to allow the activity to get the last-sent event of a given type).

Upvotes: 2

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