CODEWITHSUNDEEP
r
AME
AME

Reputation: 5300

Looping through list of data frames in R

I have a series of data frames, df1 df2, where each data frame follow this structure: 

x <- c(1:5)
y <- c(1:5)
df1 <- data.frame("Row One"=x, "Row Two"=y)

Sample output for df1:

 Row.One    Row.Two
    1           1
    2           2
    3           3
    4           4
    5           5

I put each data frame into a list dfList <- list(df1,df2...)

Now I want to loop through each data frame object in this list to replace the column names using this command:

a <- grep("One", colnames(df))
b <- grep("Two", colnames(df))

names(df)[a] <- "R1"
names(df)[b] <- "R2"

How can I structure a loop in R so that I no matter how many data frames are in the list object the column name changing commands above will be applied to each data frame?

Upvotes: 12

Views: 80538

Answers (3)

IRTFM
IRTFM

Reputation: 263481

> df1 <- data.frame("Row One"=x, "Row Two"=y)
> df2 <- data.frame("Row Two"=y,"Row One"=x)
> dfList <- list(df1,df2)
> lapply(dfList, function(x) {
                    names(x)[ grep("One", names(x))] <- "R1"
                    names(x)[ grep("Two", names(x))] <- "R2"
                    x} )
[[1]]
  R1 R2
1  1  1
2  2  2
3  3  3
4  4  4
5  5  5

[[2]]
  R2 R1
1  1  1
2  2  2
3  3  3
4  4  4
5  5  5

Upvotes: 21

Maiasaura
Maiasaura

Reputation: 32996

Or use llply (from plyr) or lapply like so:

library(plyr)
result_list <- llply(list_of_df, function(x) {
                # do the replacing
                return(x)
                })

Upvotes: 5

Se&#241;or O
Se&#241;or O

Reputation: 17432

Just use length(dfList)?

for(i in 1:length(dfList))
{
    a <- grep("One", names(dfList[[i]]))
    ... #etc.
}

Using lapply will be faster.

ChangeNames = function(Data)
{
    a = grep("One", names(Data))
    b = grep("Two", names(Data))
    names(Data)[c(a,b)] <- c("R1", "R2")
    return(Data)
}
lapply(dfList, ChangeNames) #Returns list of renamed data frames.

Upvotes: 5

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