aioobe
aioobe

Reputation: 420951

Custom JSON deserialization only if certain field is present (using Jackson)

When deserializing MyEntity (which is an interface) I either have

I've figured out how to register my own custom deserializer through a SimpleModule but I don't know how to

  1. Choose a custom deserializer based on the presense of some field (such as message above).
  2. Fallback on the "default" serializer for certain fields (such as otherEntity above).

Upvotes: 2

Views: 1845

Answers (1)

aioobe
aioobe

Reputation: 420951

Finally solved it by configuring my ObjectMapper as follows:

ObjectMapper mapper = new ObjectMapper();

SimpleModule idAsRefModule = new SimpleModule("ID-to-ref",
                                              new Version(1, 0, 0, null));

idAsRefModule.addDeserializer(TestEntity.class,
                              new JsonDeserializer<TestEntity>() {
    @Override
    public TestEntity deserialize(JsonParser jp, DeserializationContext dc)
            throws IOException, JsonProcessingException {

        ObjectCodec codec = jp.getCodec();
        JsonNode node = codec.readTree(jp);
        boolean isFullImpl = node.has("message");
        Class<? extends TestEntity> cls = isFullImpl ? TestEntityImpl.class
                                                     : TestEntityRef.class;
        return codec.treeToValue(node, cls);
    }
});

mapper.registerModule(idAsRefModule);

return mapper;

Upvotes: 1

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