CODEWITHSUNDEEP
c#
user2801706
user2801706

Reputation: 43

Finding opposite side in triangle using sine returning wrong value

I have no Idea what is wrong. I have converted my sin answer to degrees but It will not give me the correct answer but instead gave me a 4.18...... The correct output should have been around 2.8.

Input 1 = 4.9 and Input 2 = 35 On my calculator Sin(35) * 4.9 = 2.8....

output = Convert.ToDouble(Input1.Text) 
            * Math.Sin(Convert.ToDouble(Input2.Text)*180/Math.PI);

Upvotes: 2

Views: 112

Answers (2)

Jerry
Jerry

Reputation: 4408

Math.Sin() takes the angle in radians.

What you do are doing here 

Math.Sin(Convert.ToDouble(Input2.Text)*180/Math.PI)

is converting input2 to degrees.

You need to multiply by Math.PI/180 to convert degrees to radians.

Edit: So you should use 

Math.Sin(Convert.ToDouble(Input2.Text)*Math.PI/180)

Upvotes: 4

Claies
Claies

Reputation: 22323

As has been stated in other answers, your operator precedence is backwards, you need to divide Math.PI by 180 rather than dividing 180 by Math.PI. So, your function should be:

output = Convert.ToDouble(Input1.Text) * Math.Sin(
                                         Convert.ToDouble(Input2.Text)*(Math.PI/180));

Upvotes: 0

Related Questions