CODEWITHSUNDEEP
pythonbinary
JAZs
JAZs

Reputation: 29

how can i correct my python code to convert binary string into position specific code

def convertSeq(s, index):
    result = [i+1 for i,ch in enumerate(s) if ch=='1']
    result = ' '.join([str(index)+':'+str(i) for i in result])
    result = str(index)+' '+result
    return result
seq1 = "00001000000000000000000010000000000000000000100000000000000000001000000000000000"

a = convertSeq(seq1, 1)
print a

Given functoin has been created to convert 

"00001000000000000000000010000000000000000000100000000000000000001000000000000000"

into position specific code its work fine if i use

seq1 = "00001000000000000000000010000000000000000000100000000000000000001000000000000000"

as input for the code I get,

 1 1:5 1:25 1:45 1:65

as output (as expected). But when I used an input file with the contents: 

00001000000000000000000010000000000000000000100000000000000000001000000000000000 
10000000000000000000001000000000000000000010000000000000000000100000000000000000 
00100000000000000000001000000000000000000010000000000000000000100000000000000000

the output is very weird.

To me it seems that when i use 

seq1="00001000000000000000000010000000000000000000100000000000000000001000000000000000"

it is considered a string because of " " and when I use a input file so it considers 0 and 1 as individual charactera.

What method should I use so that it can take binary code input from a file containing binary code in lines and generate output for each and every line.

Sample Input:

00001000000000000000000010000000000000000000100000000000000000001000000000000000
10000000000000000000001000000000000000000010000000000000000000100000000000000000
00100000000000000000001000000000000000000010000000000000000000100000000000000000
00001000000000000000000010000000000000000000100000000000000000001000000000000000
10000000000000000000001000000000000000000010000000000000000000100000000000000000
00100000000000000000001000000000000000000010000000000000000000100000000000000000

Sample Output: 

1 1:5 1:25 1:45 1:65
2 2:1 2:21 2:44 2:64
and so on...........

As I am very new in programming I have spent my 5-6 hours on it but not succeeded.Please help

Upvotes: 0

Views: 150

Answers (3)

DevC
DevC

Reputation: 7423

you can do like this, read the whole file as string and pass to your function

def convertSeq(s, index):
    result = [i+1 for i,ch in enumerate(s) if ch=='1']
    result = ' '.join([str(index)+':'+str(i) for i in result])
    result = str(index)+' '+result
    return result

# read the sequence from file
with open ("file.txt",'r') as f:
   f_seq=f.readlines()

for line, seq in enumerate(f_seq, start=1):
    a = convertSeq(seq, line)
    print a

From the content you have given, it gives following output

1 1:5 1:25 1:45 1:65
2 2:1 2:23 2:43 2:63
3 3:3 3:23 3:43 3:63
4 4:5 4:25 4:45 4:65
5 5:1 5:23 5:43 5:63
6 6:3 6:23 6:43 6:63

You can also read the file name as arg to your program, so you don't have to hard code file name

import sys
def convertSeq(s, index):
    result = [i+1 for i,ch in enumerate(s) if ch=='1']
    result = ' '.join([str(index)+':'+str(i) for i in result])
    result = str(index)+' '+result
    return result

#take the file name as arg
seqFile = sys.argv[1]

with open (seqFile,'r') as f:
   f_seq=f.readlines()

for line, seq in enumerate(f_seq, start=1):
    a = convertSeq(seq, line)
    print a

Upvotes: 1

Duncan
Duncan

Reputation: 95692

Iterate over the file using enumerate() to count the lines:

with open(filename) as f:
    for line_no, seq in enumerate(f, start=1):
        print convertSeq(seq, line_no)

Upvotes: 1

mshsayem
mshsayem

Reputation: 18018

If convertSeq works then this should do:

line_num = 1
for line in open(filename):
    print convertSeq(line, line_num)
    line_num += 1

Upvotes: 2

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