CODEWITHSUNDEEP
javawindowspowershellbatch-file
timmalos
timmalos

Reputation: 542

Powershell vs Batch - Java command line

I used to launch a java tool with a batch like this :

java -classpath "./lib/JSanExport.jar;./lib/JSanRmiApiEx.jar;./lib/JSanRmiServerUx.jar" -Xms128M -Xmx768M -Dmd.command=command_VSPLA.txt -Dmd.logpath=log sanproject.getmondat.RJMdMain

For some reasons i need to convert that batch into a Powershell script. But when I copy the same line on my powershell script I got an error, whereas I launch it in the same workingdir.

c:\Program Files\ExportTool\export>powershell .\Run_VSPLA.ps1
Exception in thread "main" java.lang.NoClassDefFoundError: /command=command_VSPLA/txt
Caused by: java.lang.ClassNotFoundException: .command=command_VSPLA.txt
    at java.net.URLClassLoader$1.run(Unknown Source)
    at java.security.AccessController.doPrivileged(Native Method)
    at java.net.URLClassLoader.findClass(Unknown Source)
    at java.lang.ClassLoader.loadClass(Unknown Source)
    at sun.misc.Launcher$AppClassLoader.loadClass(Unknown Source)
    at java.lang.ClassLoader.loadClass(Unknown Source)
Could not find the main class: .command=command_VSPLA.txt.  Program will exit.

Do you know what happens?

Upvotes: 2

Views: 752

Answers (2)

npocmaka
npocmaka

Reputation: 57282

try to set jvm options before classpath :

java -Xms128M -Xmx768M -Dmd.command=command_VSPLA.txt -Dmd.logpath=log  -classpath "./lib/JSanExport.jar;./lib/JSanRmiApiEx.jar;./lib/JSanRmiServerUx.jar" sanproject.getmondat.RJMdMain

It searches for class named /command=command_VSPLA/txt. For batch = is a delimiter and is parsed in a different way than powershell.

EDIT

The solution given by the OP:

java -Xms128M -Xmx768M "-Dmd.command=.\command_VSPLA.txt" "-Dmd.logpath=log" -classpath "./lib/JSanExport.jar;./lib/JSanRmiApiEx.jar;./lib/JSanRmiServerUx.jar" sanproject.getmondat.RJMdMain

Upvotes: 2

izissise
izissise

Reputation: 953

Seem like it can't find command_VSPLA.txt, maybe try a full path.

Upvotes: 0

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