CODEWITHSUNDEEP
shellubuntuterminalcommand
user2763361
user2763361

Reputation: 3919

How to find disk size of sub-folders of same name

Suppose directory structure on Ubuntu is /home/f1/a, /home/f2/a, /home/f3/a and /home/f4/a. Suppose my objective is to know the disk size of folders a within each f1,f2,f3,f4 (not the size of files inside these folders but the folders themselves); and to do it while I'm in /home.

Question What's the shell command I can run from /home to get the disk size of each folder a?

In my real world example I have 60 of these directories (i.e. ~/f1/a,~/f2/a,...,~/f60/a) so a command that doesn't spam too much other information is preferred.

Upvotes: 0

Views: 543

Answers (2)

Mohammad Razeghi
Mohammad Razeghi

Reputation: 1594

this code works :

for i in `seq 1 60`
do
    du -ch ~/f$i/a | tail -n 1 | awk -F' ' {'print $1'}
done

Upvotes: 1

MattSizzle
MattSizzle

Reputation: 3175

The below will give you a break down of the folder sizes and a total at the end for all the folders no matter how many there are as long as they start with f and are in /home

du -ch /home/f*/a/

Output:

24K     /home/mgreen/f11/a/
4.0K    /home/mgreen/f12/a/
4.0K    /home/mgreen/f61/a/
32K     total

I think you are looking for something more like the following though which will let u grab a total for each /a/ folder and not the total of all of them.

for i in $(ls /home/mgreen |grep 'f[0-9]');do for d in $(ls /home/mgreen/$i|grep "a");do printf "$i$d " ;du -sch /home/mgreen/$i/$d | tail -n 1 | awk '{print $1}';done ;done

where $i equals the top level directory f1-100 and $d equals the 'a' directory. The extra loops keeps $a assigned to a variable for printing.

Output:

f11/a/ 24K
f12/a/ 4.0K
f61/a/ 4.0K

Hope this helps.

Upvotes: 2

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