Reputation: 967
I have two lists like:
list1 = ['square','circle','triangle']
list2 = ['red','green']
How can I create all permutations of these lists, like this:
[
'squarered', 'squaregreen',
'redsquare', 'greensquare',
'circlered', 'circlegreen',
'redcircle', 'greencircle',
'trianglered', 'trianglegreen',
'redtriangle', 'greentriangle'
]
Can I use itertools
for this?
Upvotes: 62
Views: 86560
Reputation: 31
Simple list comprehension will give the result
from itertools import product
final_list = [a + b for a, b in product(list1, list2)]
Upvotes: -1
Reputation: 311745
You want the itertools.product
method, which will give you the Cartesian product of both lists.
>>> import itertools
>>> a = ['foo', 'bar', 'baz']
>>> b = ['x', 'y', 'z', 'w']
>>> for r in itertools.product(a, b): print r[0] + r[1]
foox
fooy
fooz
foow
barx
bary
barz
barw
bazx
bazy
bazz
bazw
Your example asks for the bidirectional product (that is, you want 'xfoo' as well as 'foox'). To get that, just do another product and chain the results:
>>> for r in itertools.chain(itertools.product(a, b), itertools.product(b, a)):
... print r[0] + r[1]
Upvotes: 114
Reputation: 115011
>>> import itertools
>>> map(''.join, itertools.chain(itertools.product(list1, list2), itertools.product(list2, list1)))
['squarered', 'squaregreen', 'circlered',
'circlegreen', 'trianglered', 'trianglegreen',
'redsquare', 'redcircle', 'redtriangle', 'greensquare',
'greencircle', 'greentriangle']
Upvotes: 47
Reputation: 880807
I think what you are looking for is the product of two lists, not the permutations:
#!/usr/bin/env python
import itertools
list1=['square','circle','triangle']
list2=['red','green']
for shape,color in itertools.product(list1,list2):
print(shape+color)
yields
squarered
squaregreen
circlered
circlegreen
trianglered
trianglegreen
If you'd like both squarered
and redsquare
, then you could do something like this:
for pair in itertools.product(list1,list2):
for a,b in itertools.permutations(pair,2):
print(a+b)
or, to make it into a list:
l=[a+b for pair in itertools.product(list1,list2)
for a,b in itertools.permutations(pair,2)]
print(l)
yields
['squarered', 'redsquare', 'squaregreen', 'greensquare', 'circlered', 'redcircle', 'circlegreen', 'greencircle', 'trianglered', 'redtriangle', 'trianglegreen', 'greentriangle']
Upvotes: 12
Reputation: 23980
You can in any case do something like:
perms = []
for shape in list1:
for color in list2:
perms.append(shape+color)
Upvotes: 9
Reputation: 84379
How about
[x + y for x in list1 for y in list2] + [y + x for x in list1 for y in list2]
Example IPython interaction:
In [3]: list1 = ['square', 'circle', 'triangle']
In [4]: list2 = ['red', 'green']
In [5]: [x + y for x in list1 for y in list2] + [y + x for x in list1 for y in list2]
Out[5]:
['squarered',
'squaregreen',
'circlered',
'circlegreen',
'trianglered',
'trianglegreen',
'redsquare',
'greensquare',
'redcircle',
'greencircle',
'redtriangle',
'greentriangle']
Upvotes: 20