CODEWITHSUNDEEP
java
user2908533
user2908533

Reputation: 37

Dynamic value initialization in Array in java

In my code I have one vairable:

public Edge[] adjacencies;

now for initialization array is something like this:

     v0.adjacencies = new Edge[] {
        new Edge(v1, distance[0][1]),
        new Edge(v2, distance[0][2]),
        new Edge(v3, distance[0][3]),
        new Edge(v4, distance[0][4]),
        new Edge(v5, distance[0][5]),
        new Edge(v6, distance[0][6]),
        new Edge(v7, distance[0][7]) 
        };

but I want to give dynamic initialization something like this:

 v0.adjacencies = new Edge[] {
    for(int i=1;i<8;i++)    
         new Edge("v"+i, distance[0][i]); 
 };

Upvotes: 1

Views: 1622

Answers (5)

Dawood ibn Kareem
Dawood ibn Kareem

Reputation: 79875

Forget all about your variables v1, v2 and so on. Just keep them all in an array to start with.

Vertex[] vertices = new Vertex[8];
for (int i = 0; i < 8; i++) {
    vertices[i] = new Vertex();
}

vertices[0].adjacencies = new Edge[7];
for (int i = 1; i < 8; i++) {
    vertices[0].adjacencies[i - 1] = new Edge(vertices[i], distance[0][i]);
}

Upvotes: 0

Manish Doshi
Manish Doshi

Reputation: 1193

You will want to look into the java.util package, specifically the ArrayList class. It has methods such as .add() .remove() .indexof() .contains() .toArray(), and more

Upvotes: 0

Terry Li
Terry Li

Reputation: 17268

Vertex[] vertices = {v1,v2,v3,v4,v5,v6,v7};
v0.adjacencies = new Edge[7];
for(int i=1;i<8;i++) {   
  v0.adjacencies[i-1] = new Edge(vertices[i-1], distance[0][i]); 
}

Try this.

Update: I assume those v1, v2, ... are objects of class Vertex (whatever you call it) and update the code accordingly.

Upvotes: 0

npinti
npinti

Reputation: 52185

How about something like this:

v0.adjacencies = new Edge[7];
for(int i = 1; 1 < 8; i++)
{
    v0.adjacencies[i - 1] = new Edge("v"+i, distance[0][i]); 
}

I'm assuming that v1, v2, etc are strings of the form v1, v2, etc.

Upvotes: 0

mau
mau

Reputation: 258

One way to do this dynamically is to create the array with the variable length.

length = 8; 
v0.adjecencies = new Edge[length];
for(int i=1;i<length;i++)    
  v0.adjecencies[i-1] = new Edge("v"+i, distance[0][i]);

Upvotes: 1

Related Questions