Reputation: 701
In one of the column i am getting 2 values with a delimiter between it How to extract both the values
I have some thing like this Column TRN02
is 115679-5757
I need to take values before delimiter and after delimter into 2 separate columns again.
Can some one help me on this
Upvotes: 30
Views: 121255
Reputation: 18162
You can use SUBSTRING
to do this:
SELECT
SUBSTRING(TRN02, 0, CHARINDEX('-', TRN02)) AS [First],
SUBSTRING(TRN02, CHARINDEX('-', TRN02) + 1, LEN(TRN02)) AS [Second]
FROM TABLE
Upvotes: 52
Reputation: 65
update df set df.column=s.[value] FROM table df
cross APPLY string_split(REPLACE(column, 'split_parameter', '@') ,'@') s
where column like '%split_parameter%' and s.[value] not like '=%'
Upvotes: -3
Reputation: 2940
Just another way USING LEFT
and RIGHT
-
SELECT LEFT(TRN02, CHARINDEX('-', TRN02) - 1) [before_delim],
RIGHT(TRN02, LEN(TRN02) - CHARINDEX('-', TRN02)) [after_delim]
FROM your_table
Upvotes: 13
Reputation: 7119
SELECT LEFT(details, CHARINDEX ('-', TRN02 ) - 1),
SUBSTRING(details, CHARINDEX ('-', TRN02 ) + 1, 100)
FROM Your_table
Upvotes: 0